I really need help can someone who’s really good at math DM me | Mathematics | Page 1

haughty jetty Mar 5, 2024, 1:53 AM

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Hello 🙂

wintry torrentBOT Mar 5, 2024, 1:53 AM

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tall pebble Mar 5, 2024, 1:56 AM

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you can post your question here as well, increases the chances of people helping you out

haughty jetty Mar 5, 2024, 1:57 AM

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Okay I just wanted to give a reward to someone who helped me

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Cus it might be hard

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Can someone help 😣

tall pebble Mar 5, 2024, 1:59 AM

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We are looking for the perimeter of those figures

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What is the perimeter of the first figure?

haughty jetty Mar 5, 2024, 1:59 AM

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6

tall pebble Mar 5, 2024, 1:59 AM

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figure 2?

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and also figure 3 please

haughty jetty Mar 5, 2024, 2:01 AM

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I know how to do that I just need help with writing an explicit equation and recursive equation

tall pebble Mar 5, 2024, 2:04 AM

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ok so you notice this pattern

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6 * 1

6 * 3

6 * 5 ...

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so the next would be 6 * 7

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because we multiply with an odd number

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now the question is how can we write this generally

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any idea?

haughty jetty Mar 5, 2024, 2:06 AM

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Like an = (6*7)(n-1)

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Idk

tall pebble Mar 5, 2024, 2:06 AM

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ok look

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we can potray all even numbers as 2n for example where n is a natural number

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2n = 2, 4, 6, 8...

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now we want it for odd instead

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so what would we need to add to the 2n term

haughty jetty Mar 5, 2024, 2:08 AM

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Even numbers ?

tall pebble Mar 5, 2024, 2:08 AM

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how can we make it 1, 3, 5, 7...

tall pebble Mar 5, 2024, 2:09 AM

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tall pebble 2n = 2, 4, 6, 8...

knowing this: 2n = 2, 4, 6, 8...

how can we achieve this 1, 3, 5, 7...

haughty jetty Mar 5, 2024, 2:11 AM

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-1 from each number so (1-)

tall pebble Mar 5, 2024, 2:11 AM

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well done

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so it's 6 * (2n-1)

sudden locustBOT Mar 5, 2024, 2:12 AM

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adonhs

tall pebble Mar 5, 2024, 2:12 AM

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did you understand?

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For the recursive formula ask yourself what is the difference between you n-th and your (n+1)-th term

pliant juniper Mar 5, 2024, 2:18 AM

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the question states only the outside lines

tall pebble Mar 5, 2024, 2:20 AM

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oh shoot right

pliant juniper Mar 5, 2024, 2:21 AM

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no problem
you just have to subtract 4n-4 from each figure.

tall pebble Mar 5, 2024, 2:22 AM

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haughty jetty

I guess that'S why they have a table for

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so yoou dont make silly mistakes and work with structure

half warren Mar 5, 2024, 2:25 AM

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isn't it 4(number of hexagons)+2=4(2n-1)+2=8n-2
because it's 4 sides per hexagon + the 2 from both ends

pliant juniper Mar 5, 2024, 2:33 AM

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basically. its the same as saying:

okay we have 6times an uneven amount 6(2n-1) but also for 4n-4 less sides, because of the hexagons inbetween. so we have 12n-6-4n+4, so we have 8n-2

#I really need help can someone who’s really good at math DM me