#got it wrong??
43 messages · Page 1 of 1 (latest)
Because that's the area for half the triangle 😄
What do you need to do additionally?
Ye for the "right" triangle
yea
but it's looking for the whole
the area of the whole triangle
Oh
Uhh I guess i just multiply 334 by 2 right?
Im not sure if it's another process
yea
,w (1/2)(14)(48)
,w (1/2)(14)(48) * 2
.close
Post marked as solved by @quasi kiln.
Use .unsolved if this was a mistake.
Post marked as unsolved by @atomic iron.
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I forgot about this but shouldnt the two areas be equivalent considering that it's an isoceles triangle?
Multitasked doing physics
<@&286206848099549185>
yes
you literally split the triangle in half
as did you the 28m
If it's too hard just use herons formula to find it
S = side (a + b + c)/2
Which here
Is 64
So it's root(s(s -a)(s-b)(s-c))
Which is
$root(64 x 14 x 14 x 36)$
Aqua.
$root(64 x 14 x 14 x 36)$