#Dont know whats wrong with my approach
57 messages · Page 1 of 1 (latest)
no its surface area method
Oh surface right
The first thing I see is since it's around the x-axis why did you solve for y?
adonhs
I appreciate it, ill try this out
This calculus video tutorial explains how to find the surface area of revolution by integration. It provides plenty of examples and practice problems finding the surface area generated by a region or curve when rotating about the x axis or y terms. This video provides the two integral formulas that you need and how describes how to find the ra...
haha
Also for the derivative it's dx/dy
You differentiate with respect to y
reversed
,rotate
no i plugged in claculator
What are you getting?
,w 2pi * Integrate[(10+3y²)Sqrt[1+(6y)^2],{y,0,1}]
Do you have to give in an approximate value?
no i need to plug in the full value
now that's weird
like 0.0001 more or less surface matters
yes
yes it did not work
You can't use sinh because you are not allowed to?
seems like you should use this
adonhs
ill try that out
oh i know the mistake we did
Here the radius R(y) = y
but we wrote instead of y we wrote 10 + 3y²
Shouldn't look that complicated the result
i just tried it but that dosent work either
,w Integrate[2pi y Sqrt[1+(6y)^2],{y,0,1}]
It works man, I appreciate you with staying with me for this long