how to solve this ? :D

[ivory crow]

With which value of m does the equation (m+1)(x^2)-4x+m+2=0 have one solution. Answers (-3;1;2)

[zenith atlas]

One solution means b^2 - 4ac = 0

[ivory crow]

yeah i know

[ivory crow]

and i got D=-4m^2-12m+8

[zenith atlas]

What's D?

[ivory crow]

should i do second time?

[zenith atlas]

Did you compute b^2 - 4ac there?

[ivory crow]

yeah

[ivory crow]

and got this

yes

[zenith atlas]

Yep

[ivory crow]

and now that?

[zenith atlas]

Well this is b^2 - 4ac

We're looking for b^2 - 4ac = 0

[ivory crow]

yes

[zenith atlas]

Hm, I get $-4m^2 - 12m + 8 = 0 \iff m^2 + 3m - 2 = 0$, so $m_{1, 2} = \frac{-3 \pm \sqrt{17}}{2}$

I'm extremely sleepy today, might wanna check if I did everything correctly

[ivory crow]

yeah i know, must be exercise error

[ivory crow]

i did everything same

thanks

.solved

[neon ravine]

Solved

Post marked as solved by @ivory crow.

Use .unsolved if this was a mistake.