#Combinatorics
105 messages · Page 1 of 1 (latest)
i am selecting two random days from the year (366 days)
what are the chances of me selecting
Monday
and then tuesday
there are 53 mondays in the year
and 53 tuesdays
So If 1/2 is Monday and 1/10 is Tuesday, does it count?
Interesting
yeah
i know that
would it be something like 53C1 + 53C1
cause like
selecting one monday
is
53C1
and then selecting a tuesday
is 53C1
just add them together
boom
chances of getting monday and tuesday
right?
or am i thinking about this wrong
yep, it seems flawless
And the denominator will be randomly select two days
366C2
You’re correct
no need for denominator, im just getting the chance of selecting monday and tuesday together
not tryna find uh
decimal/percentage
so
through what i said
i can write down
there are 106 possible ways to select Monday with Tuesday
53*53=106?
i didnt multiply them by each other
Wait, Monday must stay before Tuesday, right?
no the order does NOT matter
selecting monday then tuesday
I see XD
then it’ll be 53*53
Why would it be 53+53?
wait why would it be 53*53
yep
How many in total?
you are right
yesss
Np
and uh one more question
Sure
this one should be easier now
if im selecting monday and wednesday
it would just be
53C1 * 52C1
Any more questions?
not at the moment, i need to calculate all the possible outcomes for my gambling game
😭 gonna take ages with like 40 different outcomes but womp womp
.close
(bot is down i believe)
@clever void
yep hes asleep
.close
hes back
W
.close
Post marked as solved by @buoyant beacon.
Use .unsolved if this was a mistake.
goated