#integer word problem
31 messages · Page 1 of 1 (latest)
You do the prime factorization of 2024
then what do i after that
If you want them to be integers, the denominators must cancel with the numerators.
If you have 2^n in the denominator you need at least 2^n in the numerator.
Likewise, if you have 11^n in the denominator you need at least 11^n in the numerator.
@elfin flint Have you finished solving this question?
noðŸ˜
1012
Factor
Factorization
okay, how many are there?