#cyclic quadrilateral question
80 messages · Page 1 of 1 (latest)
Ratio means x/y = 3/7
You are gonna have to write y based on x from this equation, so you can use it for the actual part (circle)
the circle isnt relevant to this equation is it ?
No it is not related to the equation, the question has given that so you can make a “system” using it and find the values of x and y
yes i do know that information
and i know this
$\frac{x}y = \frac37$
ned
yeah….then you have acquired the key
What’s your confusion?
just dont know how to put it in the equation to get the answere
okay ?
Please pay attention to this similar example
Using the equation x/y I will conclude that
And I isolate y to see that y values 2x/3
BECAUSE y values 2x/3, we can replace y in the equation below to have only one variable
You basically solve the equation
And you find the value of x, you can also find the value of y since y values 2/3 of x
okay okay so 7/3 x = y
Exactly
so what do i do with the y now ?
Man, you are so zealous 💀
Do this
They should pay you tuition for that
lol
follow the steps mentioned in the example above
how did you get 5x here ?
x + 2x/3 = 3x/3 + 2x/3 = (3x +2x)/3
and why did you add another 2x ?
@dawn girder still clueless mate because i still dont know how tf did you get 5x/3
all i know is that from my equation , i have 7/3 x
Since y = 2x/3
I can replace y in the equation x + y = 10
so
I change y to 2x/3
I get
x + 2x/3 = 10
does that make any sense?
yes but then how did you get 5x
you found the common denominator
yep
but i didnt think you needed to do that
x is basically x/1 right?
yep
but we need something that is like /3 sooo it can match with 2x/3
so then my equation is 10x/3 = 180
Yep that’s correct!
x is 6 then ?
Yez
Oops
10x/3 = 180
you divide by 10 and multiply by 3
x = 180 * 3/10 = 54
my bad I didn’t check that
but thanks anyway
You have found the arc BD correctly
but you should think about BFD once more
the angle bfd is given to me
It’s not 😊
It is legit given to me
anyway thanks for your help i will just ask my teacher. thank you for your time
.close
Post marked as solved by @hard yacht.
Use .unsolved if this was a mistake.