Can someone do these problems!!

[wooden elm]

I can solve

[hollow citrus]

Thank you

can i see the work too

[wooden elm]

v(t)= 2t² -14t + 24 , is basically;
ax²-bx+c

We will have 2 results bro

[hollow citrus]

ok thanks

[wooden elm]

No

This is not The results

calm down

[steel lantern]

well i guess find its minima ( parabola opens up) for 2nd ques

[wooden elm]

@hollow citrus bro

[wooden elm]

....

[steel lantern]

then determine in which intervals the slop is positive

[wooden elm]

Its minima?

[steel lantern]

its

yes

a is positive

use desmos

[wooden elm]

Idk what is demos

[steel lantern]

graph calculator

[wooden elm]

A

[hollow citrus]

oh ok

[wooden elm]

The minima is 5/2

T

But the answear is A

[steel lantern]

wut

[wooden elm]

Just 1 min

[hollow citrus]

im so confused

[wooden elm]

Calm

My english is bad

[hollow citrus]

its ok

[steel lantern]

try use graohic calculator for help, its very usefull for beiginner calc and even advance

[hollow citrus]

my math is bad

can you guys do this one instead

i think i got the first one

[wooden elm]

I dont know how to get the acceleration function

My bad

[hollow citrus]

all good

do you know how to do the problem i jsut sent

[wooden elm]

I just know the minimum value of "T"

[steel lantern]

well yes find the intersection of both function 1st

[steel lantern]

well actually the min value of 3.5

i mean min value was 3.5

[wooden elm]

5/2 '-'

And the maximum is 9/2

[hollow citrus]

i solved the original problem btw

[wooden elm]

Pls can you share?

[steel lantern]

here how the fucntion form both question looks like

[lament quest]

Do you know how to integrate

[hollow citrus]

nope lol

[lament quest]

Do you know how to take a derivative

[hollow citrus]

i use photo math

[lament quest]

💀

[steel lantern]

what

[lament quest]

Are you in calculus

[hollow citrus]

ya

[wooden elm]

This is fail

[lament quest]

Why are you taking it is it a prerequisite

[steel lantern]

what

[hollow citrus]

idk

i m trolling

[steel lantern]

tf

5 messages more btw

[wooden elm]

Thee relation of v(t) = 2t² - 14t + 24 is equal to 2 results to (t).
T1=9/2 Maximum value
T2= 5/2 Minimum value.
To find the relation in the funct v(t) to v(a) you need to resolve the v(t), t = 5/2 or 9/2. Is impossible to know the true value about the results in this answear because will be results in v(A1) and v(A2), the answear dont cit any results to make the relation with then

[wooden elm]

This is just graphs not results

[steel lantern]

ik, but it helps to solve problem much easier

[steel lantern]

but hey, a parabola cannot have both minimum and maximum at the same time

if a is - , then it have maxima, if a is + it have minima

[wooden elm]

The value of parabola is
2t²-14t+24 , t 》0
y = ax² + bx + c
This is second degree equation, you will get 2 results

Lack of information to solve the problem

[hollow citrus]

burhh

hahaa

ok

[wooden elm]

it asks for the function associated with acceleration, but does not say whatever roots of A we should use

[hollow citrus]

ah ok

well what do should i put down on the test lol

[wooden elm]

Even if we get both results it will be wrong, it does not ask for the maximum or minimum value

[wooden elm]

Idk

Bad teatchear XD

[hollow citrus]

hahahaha

thank anyways guys

[untold walrus]

!nosols

[pliant jackal]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[untold walrus]

!noans

[pliant jackal]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.