Help

[uncut saddle]

I’m not sure what the best way to handle the (v)^2 would be

Or how to rewrite 3sqrtc

[glass quiver]

its just chain rule really, the stuff inside only needs the power rule

you can write the cube root term as x^(-1/3)

[uncut saddle]

Thanks

[uncut saddle]

I’m not familiar with chain rule

[tranquil lantern]

if you expand the term, you should get> x + x^(-2/3) + 2x(1/6, if you are familiar with this formula n x^(n - 1) then you should be able to differentiate it

[uncut saddle]

Got it thanks

.solved