#Ratonal Function

53 messages · Page 1 of 1 (latest)

vast bison
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idk what the fuck these words mean and btw this is finnish.

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severe arrowBOT
vast bison
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queaston a) please

narrow holly
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maybe translate from finnish first?

vast bison
narrow holly
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okay so the domain

narrow holly
vast bison
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x + 2

narrow holly
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more precisely?

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or like

iron siren
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more exactly

narrow holly
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we can divide by x+2, but not when it equals to..

vast bison
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x = 0

iron siren
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almost

narrow holly
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essentially

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x+2=0

vast bison
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oooohhh

iron siren
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spoilerrr

narrow holly
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solve for x

vast bison
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x = -2

narrow holly
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mhm

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so that's the value that is not within the domain (definition set)

vast bison
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but the thing is how can i put it in professional way

vast bison
narrow holly
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there is a vertical asymptote at x=-2

vast bison
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idk how to futhrer than taht

narrow holly
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and for the rest of real numbers f(x) is defined

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so the domain is reals except -2

vast bison
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oooohhhh

narrow holly
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$\bR \setminus {-2}$

peak apexBOT
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artemetra

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vast bison
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oohhhhhhh

iron siren
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ohhh

vast bison
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thank you

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god bless you

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one question

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what doest that R mean

iron siren
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real numbers

vast bison
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oh okayt

iron siren
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artemetra taught me math yk

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he a good teacher

vast bison
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thank you boss

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how can i close this

iron siren
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.solved

severe arrowBOT
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Solved

Post marked as solved by @iron siren.

Use .unsolved if this was a mistake.

vast bison
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.solved

iron siren
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it is already

narrow holly
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it's closed

vast bison
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hahaha

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my bad

narrow holly
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all good