Partial differentation

[graceful cedar]

Why is this incorrect

the homework was already handed in, i just want to know why this was incorrect

[next basin]

Adler

[foggy kayak]

I hadn't seen that it was with partial derivatives.
you have the calculation wrong at the end

$(\sqrt{15}+\frac{9}{\sqrt{15}})*(-5)=?$

[next basin]

Adler

[graceful cedar]

wdym

is it just that equation?

that makes no sense

the equation for df/dt is as follows:

for 2 dimension

thats only dx/dt * partial derivative with respect to x

which is what i got for one plane, but the other plane needs to be considered as well

[graceful cedar]

.

[foggy kayak]

We are talking about the same. And no, I was not calculating df/dx of dx/dt. I was just too lazy to put the derivative of the root

$\frac{df}{dt}= x* \frac{1}{2\sqrt{x-3y^2}}(\frac{dx}{dt}-6y\frac{dy}{dt}) +\frac{dx}{dt}\sqrt{x-3y^2}$

[next basin]

Adler

[foggy kayak]

$\frac{df}{dt}= [{\frac{x}{2\sqrt{x-3y^2}}+\sqrt{x-3y^2}}]\frac{dx}{dt} + [\frac{-6xy}{2\sqrt{x-3y^2}} ]\frac{dy}{dt}$

[next basin]

Adler

[foggy kayak]

Arranging it to take the form you expect.

[graceful cedar]

so whats the problem

[graceful cedar]

.

[burnt cairn]

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[graceful cedar]

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