Hi, I've tried this one multiple times, and this is the already 'expired' try, so I'm on a new one, but I come up with what I think is the right answer each time and even cross referenced with the other angles, so not sure what I'm doing wrong.
#Trig Application Problem; Isosceles triangle word problem
cinder iron
celest stumpBOT
pastel epoch
Hi, I've tried this one multiple times, and this is the already 'expired' try, s...
can you explain how you got 21?
cinder iron
yes, I will use the new numbers from the new problem
so I am now given the two people are 28 feet from each other, and the angle of elevation from each person to the top of the flagpole is 60 degrees. So I drew an isosceles triangle, and labeled the base 28 feet, and both of known angles as 60. I drew a line cutting the triangle down the middle to denote the height of the flagpole. If you divide 28 in half, that would create two right triangles with the shorter sides measuring 14 feet.
So I used the tangent function to find the height:
tan60degrees = height/14
which after getting height (x) on its own side, would be 14tan60degrees = x
now I get 24.248 and I am to round to the nearest whole number which is 24, and I just typed it in to find out I am still wrong lol
pastel epoch
ok wait you might have a wrong understanding of the problem
so if you view it from the top, you should actually be looking at a right isosceles triangle
the angle of elevation will NOT be seen in an "aerial view" of the problem
because the angle of elevation refers to the angle at which, say, an ant must look up in order to see the top of the flagpole
so in an aerial view
you have 1 person to the north and 1 person to thr east
that means there's a right angle at the flagpole
and the hypotenuse is precisely the distance between the two people
