tan 13pi/12

[terse jasper]

Keep getting wrong answer

[quaint rapids]

Hello! do you still help?

[quiet scaffold]

ok so

tan(13pi/12)= sin(13pi/12)/cos(13pi/12) right?

but 13pi/12=16pi/12 - 3pi/12 = 4pi/3 - pi/4

so now you have tan(13pi/12)=sin(4pi/3-pi/4)/cos(4pi/3-pi/4)

and now you use the formulas for sin(a-b) and cos(a-b) and you’re done!

[quiet scaffold]

oups you wrote everything right just not the last equality mb

[vagrant epoch]

excuse moi

[quiet scaffold]

?

[vagrant epoch]

d'accord

[quiet scaffold]

but🤣

wdym

[terse jasper]

Thank you 😍

[vagrant epoch]

.solved