Calculus help needed!

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|a-x²| ≤ 5

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may I ask why? And how can I deviate and produce an answer afterward?

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that was nonsense

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pardon?

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I wrote nonsense

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it do be like that sometimes

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Are you familiar with circles?

Like x² + y² = r²

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I do not, however I can learn and understand it in the process

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Well my thought is that using x² + y² = r²

We can solve for y = ± √(r² - x²)

You're thinking now ok

but hear me out

r is the radius right

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yeah

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and the circle is centred

So let's say what should be r if we want it to have radius 5?

it'd be 5

r = 5

and knowing how a circle looks like

it's only defined between that domain

between -5 and 5

so you'd get y = ± √(5² - x²) = ± √(25 - x²)

[ruby ingot]

oh yeah It kind of makes sense, though are there proof that it always work though? I mean this way is kind of foreign to me and I'm not too sure about the legitimate of it

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that'd be one approach

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great idea though I'll give you that

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another one is a - x² is basically a parabola open downwards

so basically you should ask yourself how should a be (a is the shifts up or down) so that the parabola is positive between -5 and 5

or basically has its roots between -5 and 5

,w plot -x^2

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imagine this

and how should be so that the parabola is positive between -5 and 5

a should be a positive value

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ohhhh right, thats one way to put it

aight, thanks man

have a great day and thanks for the help

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really? ok

glad for the help lol

i confused you first so i was like i couldnt let you down like that😅

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LMAO tbh

when you said "really?"

i got a sudden surge of concern

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tbh i feel that

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yeah now I think i have to find more exercises like this to try this out lol

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it was a weird way of me saying that

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you didn't let no one down even when you answered wrong dawg, tbh any help is appreciated in all capacity

cheer up and have a great day man

i mean thats how I usually roll

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thank you appreciate people like you

you just made my day

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gladly

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.solved