i have no idea how to use the unit circle for question d.
any help would be really appreciated
#pls help for d
solid adder
empty pineBOT
outer oxide
i have no idea how to use the unit circle for question d.
any help would be real...
First, see x as an angle (between 0 and 2pi). That's the trick to use the unit circle
Next, remember where to read cosine and sine on the unit circle. This should guide you to the answer
solid adder
oh ok
do i have to input the angles from the unit circle into sin(x) < cos(x)?
or do i simplify it
outer oxide
wdym ?
Your angle is x basically
You have to find out for what angle x we have sin(x) < cos(x)
outer oxide
do i have to input the angles from the unit circle into sin(x) < cos(x)?
If you meant try with usual values as π/2, π/4 etc then yeah you can definitely do that to get an idea of the answer
solid adder
ohh ok
im gonna try to see if i can work it out now
ngl im still really confused about how to do this whole thing
outer oxide
You can try to look at the values for which sin(x)=cos(x). This will define the bounds of the set you're looking for
If you don't like the unit circle, another method is to graph both sin(x) and cos(x) on the same graph
solid adder
i think i have a better idea on how to do it now
how would you know which values are sin(x)=cos(x)? also thanks for the help too
NVM
got it now
vale rover
So if I read it correctly, the question is saying x is an element on the interval [0,2pi]. Graphing cos x and sin x we can see that sin(x) is less than cos(x) at 0,3pi/2,2pi.
solid adder
i got this working out
its the right answer
but doesn't really make sense to me
bc sin(pi/3) isnt less than cos(pi/4)
.close
empty pineBOT
Solved