i need help with probablity tree diagram

[ember pelican]

help

[agile stump]

Probability of red red P("red red") is the product of their paths

[ember pelican]

so do i need to multiply first crossing red and second crossing red or?

[agile stump]

yes

[ember pelican]

aight ill do it and ill thell u what it says

so i got 1 over 6

and its inccorect

[agile stump]

how did you multiply???

4/5 * 3/4 ?

[ember pelican]

where did u get 3/4?

[agile stump]

first crossing, second crossing?

.

[ember pelican]

ah yh

i did

[agile stump]

how did you get 1/6?

[ember pelican]

im js on a dif question

its the same tho

[agile stump]

no

[agile stump]

yea here you got different probabilties

[ember pelican]

ive done 5/6 and 1/5 and it is not correct

ive multiplied

[agile stump]

The probability that both show red is 5/6 * 1/5 = 5/30 = 1/6

[agile stump]

this

it literally says that both are red

[ember pelican]

yh i type it in and it is incorrect i got the same thing

before

[agile stump]

maybe it's in percent?

or you need tor round or something

nah it says as a fraction

[ember pelican]

maybe it only says simplify

[agile stump]

simplest form 1/6

[ember pelican]

so thats fraction

lol i need to try and get this or messege my maths teacher to fk off

[agile stump]

haha

[ember pelican]

so it should be 1/6

[agile stump]

yes

[ember pelican]

its wrong bro im bout to go crazy

[agile stump]

you wanna make me question my life decisions

[ember pelican]

last question maybe we get it

i alr told him to fk off btw

[agile stump]

If the same principle doesnt work, then something is off

[ember pelican]

its 3/5

and its wrong

[agile stump]

🤯

[ember pelican]

alr ty for helping lol im going crazy lol

cya

[agile stump]

i'd play rust too

[ember pelican]

wdym

[agile stump]

i mean i'd be fed up too at this point and just play some video game lol

[ember pelican]

yh

im playing with my friends and that one question is bugging me lol

[agile stump]

chances are maybe the teacher is bugging and he actually means the probability that both lights are the same, but this is so stupid if that were truew

[ember pelican]

the teacher is calm but like he picks topics and it auto selects the questions

[crude light]

P(both red/both same color)

[ember pelican]

so i might have to tried that

[ember pelican]

wdym by same colouir

[crude light]

are you studying bayes' theorem?

[ember pelican]

no

[crude light]

the problem says:

then the total possibilities are
both red + both green

[ember pelican]

but its probability tree diagram not bayes' theorem

and thats ther awnser?

[crude light]

no

[ember pelican]

so both red + both green is the awnser or is there smth aftr

[agile stump]

so the condition is that before red red happen, both lights must have been the same

[ember pelican]

im confused

what do i do

[agile stump]

Adler is right

gosh

[agile stump]

The probabilty P(B) would be green green or red red

since before red red happens, both lights must haven been the same color that's the condition

[ember pelican]

yh

[agile stump]

You are calculating under the condition that both lights were the same, that red red occured

so really i was bugging not your teacher LOL

[ember pelican]

alr

so do i both red + both green?

[agile stump]

for p(b) yea

p(a) would be red red

and p(B | A) is a little complicated

[ember pelican]

what do i do to get it

p(b) divided p(a) or?

[crude light]

I think you can do it without bayes, just taking both red-red + green-green =100% so what is only red-red?

[agile stump]

I think P(B|A).P(A) = P(A ∩ B)

[crude light]

is not P(B|A) = 1 ?

red-red are already both same

[agile stump]

P(B|A) would be that if the lights have been red red that it will be either red red or green green?

[agile stump]

I've done this now

venn diagram i mean green green*

[crude light]

if P(A|B) = P(both red| both same color)
then P(B|A) = P(both same color| both red)

[agile stump]

yea

that's what i meant

[ember pelican]

so what is the awnser?

[crude light]

it's okay, it's the same
P(A|B) = 1* P(A) / P(B) = P(A) / P(B) = (both red)/(both red +both green)

[ember pelican]

so the awnser should be 3/5?

[agile stump]

yea i ended up with the same

(3/5) / (37/50) = 30/37

using bayes

[ember pelican]

IT WORKED!!!!!!!!!!!!

FKING FINALLLLLLLLLLLLY

I LOVE YOU @agile stump @crude light

ty so much guys

[agile stump]

damn i feel so ashamed hahahaha

without Adler I would been lost

[ember pelican]

its fine lol

[agile stump]

.solved