#Proving O<1 in an ordered field
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Suppose 0>=1
0=/=1 because 0 is the additive identity and 1 is the multiplicative identity
So the only possibility left would be 0>1 but that contradicts the assumption
How does 0>1 contradict 0>=1
2 is greater than 1 but 2 is also greater than or equal to 1
!original
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