#little integral help
42 messages · Page 1 of 1 (latest)
,tex $$f(x) = \int_{x}^{2} \frac {1}{ \sqrt[2]{1 + y^3}}$$
$$\int_{0}^{2} x f(x) dx = 1$$
@supple nacelle
Use property four
whats property foru
Ohhh
Yeah thanks
Never thought of using that property because of the bad looking limits lol
Can you help in another one
Q 114
This is my working
If you understand my bad handwriting
I can't integrate after the last step
If it is in the form of sin and cos with bad powers always take tanx as variable
Let me show you
Oh yeah
But is my working correct?
t^-2/5 will be cosx.
,rotate
In your working you put sin^-5/2 wrong
Check your variable there
It’s will be some value so I called it I and manipulated to form another integral having the same value and added them to simplify
Ah ok thanks
It should be (1-t^-4/3)^1/2
Nah mine is not solvable further I think
.close