how do I I find the circumventer if my y=mx+b is just constant

[reef dew]

I’m not sure if I’m going toward the right direction, can someone help me figure this out please?

[feral steeple]

i think dont go this way

just assume a point x,y equidistant from thesse three point

thus a circle and its radii

so use distance formula

[reef dew]

I'll show you an ex I did from in my notes

[reef dew]

This what Im trying to do

[feral steeple]

so you r going from the definition of circumcentre

[reef dew]

Yes

[feral steeple]

so this is also true

you can proceeed with that'

[reef dew]

But how do I find the circumcenter if the equation I have is just

[feral steeple]

actually there are 3 methods that i m rememberingn now

[reef dew]

x = number

[feral steeple]

of a triangle

?

[reef dew]

Circumcenter of a triangle yes

[feral steeple]

i meant that eqn

side of traingale

?

[reef dew]

Wdym

Like a^2 + b^2 = c^2 i cant really use py theorem

[reef dew]

If youre referring to that then idk

[feral steeple]

leave that

so there 3 methods

that i know

first definiion

but for that you should be very clear with graph

or image

in your mind

then assume a poit

point

and 3rd is assume general eqn of circles

[reef dew]

Ye i really cant visualize this

[feral steeple]

and satisfy it with 3 points

[reef dew]

The waht

[feral steeple]

for coordinate geometry you should be

and you cab do it with practicing questuion

[reef dew]

Can I just stick to the method the note packet has

This is already confusing

[reef dew]

Not at this lvl at so ye

[feral steeple]

ok

[feral steeple]

you can use 2 methods

they are basic

[reef dew]

ok

What am i using

Im stuck

[feral steeple]

you r using definition

without visualising the question proeprly

[reef dew]

Im completely lost rn 🗿

[feral steeple]

so restart

with making a rough diagram

for clear mindset of what to do

[reef dew]

What diagram am i suppose to draw

I thought we were just doing this mathematically

[feral steeple]

wait

[reef dew]

Im gonna take a nap

[feral steeple]

like this

[reef dew]

we do this later pls

[feral steeple]

so heres a diagram

[feral steeple]

ok

[reef dew]

@feral steeple where were we im back

[feral steeple]

so

just try to make a rough figure

also

if i m not wrong this is a right angled triangle

so if you werre asked to find orthocentre

then its just right angled vertex

so no need to solve

thus

[reef dew]

Sorry i didnt get the notif

We're doing it mathematically

@feral steeple They're asking me to find 2 equations of perpendicular bisectors

I gotta find equations

[feral steeple]

give me the questions

@reef dew

[reef dew]

:/

[feral steeple]

ok

so

see the figure

[reef dew]

I have no idea what to do since i missed friday

Ye

[feral steeple]

for every question

[reef dew]

Wdym

[feral steeple]

make a diagream

now bisector of side on y axis is

y = 1

right?

[reef dew]

I dont know

[feral steeple]

as it would be parrallel to x axis

[feral steeple]

midpoint of 0,3 and 0,-1 is/

?

[reef dew]

(0,4)?

Wait no

[feral steeple]

....

do oyu know midpoint formula

[reef dew]

We use (X + X2/2 , Y1 + Y2/2)

yes

yes

[feral steeple]

so do

[reef dew]

I just did

[feral steeple]

x = 0+0/2 = 0

[reef dew]

wait nvm

Its (0,2)

[feral steeple]

y = [3 + (-1)]/2

bruh

y = 2/2

y = 1

[reef dew]

Crap mybad

ye u right

[feral steeple]

divide by 2

so

[reef dew]

(0,1)

[feral steeple]

now this would be parallel to x axis

right

[reef dew]

Uh i think ye

[feral steeple]

it would be

so its eqn is y = 1

now for side parallel to x axis

base side

midpoint of 0,-1 and 6,-1

[reef dew]

What am I suppose to look at

Oh

[reef dew]

Yes

[reef dew]

This is for the first example on my packet right?

not the 2nd one right

[reef dew]

@feral steeple Let me know when you come back

[feral steeple]

yes

[reef dew]

Where were we

uh

[feral steeple]

so

heres our rough diagram

now to find perpendicular bisectors

[reef dew]

yes

[feral steeple]

we can use simlpest sides

base and height

[reef dew]

Which one is the base

[feral steeple]

the horizontal one

0,-1 to 6,-1

so cn you tell me the eqn of its perpendicular bisector

[reef dew]

Its the midpoints right

So it should be (x + x2/2, y + y2/2)

I think

[reef dew]

So what are we using these sides for

[feral steeple]

wait

[reef dew]

[feral steeple]

to find perpendicular bisectors

[feral steeple]

yes

as they are easy to solve

[reef dew]

(3, -2)?

Is that our midpoint

[feral steeple]

how dude

isnt it 3,-1

and thus the bisector is parallel to y axis

so eqn => x = c

here its x=3

[reef dew]

Wiat whauh

Waht

[feral steeple]

thjis you will need to remember

[reef dew]

-1 + (-1)?

= -2

[feral steeple]

/2

[reef dew]

Oh crap ye

[feral steeple]

so the slope of base is 0 right

[reef dew]

Yes horizontal slope

[feral steeple]

so slope of perpendicular be x

then x = infinity

as its vertical

x = tan 90

so $y + 1 = \infty(x - 3)$

[rotund owl]

ᴰᴱᴬᴰ ★ ᴋɪʟʟᴇʀ ⁰⁴

[reef dew]

I thought this still geometry

[reef dew]

Like 90 degree right because of pointing up right?

[feral steeple]

then $\frac{y+1}{\infty} = 0 = x-3$

[rotund owl]

ᴰᴱᴬᴰ ★ ᴋɪʟʟᴇʀ ⁰⁴

[feral steeple]

x = 3

[feral steeple]

yes

[reef dew]

Uh

What if i had to use others like sin cos and tan

When should you use a specific for a specific angle

[feral steeple]

slope is tan a only

[feral steeple]

just put the value

[reef dew]

like waht

[reef dew]

@feral steeple

Uh real quick so im trying to find the midpoint right

Find the coordinates of the circumcenter of the triangle with the given vertices.

D(-7,-1), E(-1,-1),\ F(-7,-9)

So I chose DE

Plug in values into (x + x2/2, y + y2/2)

(-7 + (-1) / 2, -1 + (-1)/2)

(-4,-1)

<@&286206848099549185>

[quick musk]

I didn’t read all of the message but have you tried using the equations of the perpendicular bisectors of the vertices

[reef dew]

Yes I have

[reef dew]

<@&286206848099549185>