#Limits Question

42 messages · Page 1 of 1 (latest)

strong scarab
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Can someone explain to me why the limit went to the exponent for e^f(x)

rough pewterBOT
warm plover
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Hence if f tends to 2 then exp(f) will tend to exp(f(2))

strong scarab
warm plover
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Here you have exp(f(x))

strong scarab
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e^f(x) yeah

warm plover
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And you know the limit of the inside, because f(x) -> f(2) when x goes to 2

strong scarab
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the limit of f(x) is given with the question

warm plover
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Let's call this value y

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y=f(2)

strong scarab
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it gives the lim x->2 f(x) = 0

warm plover
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Okay then y=0

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Then, you put this in exp

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So you want to know the limit of exp(y) when y approaches 0

strong scarab
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I think what tripping me up was the fact that I did questions such as lim x->5 of x^3 becoming [lim x->5 (x)]^3 (composition rule)

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like in this part the limit goes to the inside function

warm plover
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Yep, this is the same idea

strong scarab
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yeah the main difference is that the limit went to the exponent

warm plover
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Oh

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But the exponentiation is also a function

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Like the cube function

strong scarab
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oh so technically is should be written as [lim x->5 (x)]^(lim x->5 (3))

warm plover
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Remember that $e^y = exp(y)$

dense pastureBOT
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Twenty

strong scarab
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what does exp(y) mean

warm plover
warm plover
strong scarab
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since its e^x

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or e^y

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it will go to the exponent

strong scarab
warm plover
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Cause this time it's e^x, so the e doesn't change and the x is the variable so this is where the limit appears

warm plover
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With a certain constant e

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e ≈ 2.7182818 something

strong scarab
strong scarab
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thanks for the help ❤️