#Need help pls Integral

116 messages · Page 1 of 1 (latest)

frank slateBOT
floral shoal
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<@&286206848099549185> PLS

pearl sand
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So we have a sphere with 4cm radius and a hole into the sphere was drilled. The hole has a radius of 1cm. All right

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What formula do you know for the volume of a sphere?

floral shoal
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R=4,r=1

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the only thing that I dont understand is what is the +h and -h

pearl sand
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So you actually have to integrate

floral shoal
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exactly

pearl sand
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I would need to show a picture

floral shoal
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ok

pearl sand
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do I get your agreement sir?

floral shoal
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yes

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I dont understand, do I send a picture ?

pearl sand
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no me wait

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This is what I think is going on

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The blue one is the ball and the red is the whole

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subtracting both from each other gives us basically a new ball with radius h

floral shoal
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this is the picture with the problem

pearl sand
floral shoal
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ok

pearl sand
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and I though it would be h = R - r

floral shoal
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same thing

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so h=3

pearl sand
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I'd say so

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$\int_{y=-h}^{y=+h} \pi(x^2-r^2)dy$ you should use?

civic schoonerBOT
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adonhs

floral shoal
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yes

pearl sand
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I mean if we integrate by y then we need something with y

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x² + y² = r²

x² = r² - y²

floral shoal
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and x^2=15 and r^2=1

pearl sand
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is this the solution of the task?

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or a hint?

floral shoal
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Its what I have to do

floral shoal
pearl sand
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ok...

floral shoal
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Look what I did

pearl sand
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yeah my neck broke

floral shoal
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I just dont know what is h+ and -h

pearl sand
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,rotate

civic schoonerBOT
pearl sand
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it says h² = R²-r²

floral shoal
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ok

pearl sand
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then it follows $h = \sqrt{R^2-r^2}$

civic schoonerBOT
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adonhs

floral shoal
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yes

pearl sand
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why is x² = 15?

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why is y = 1?

floral shoal
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4 square + 1 square = 15

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My friend just tell me what to do without my picture

pearl sand
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ok

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I would substitute x² = R² - y²

floral shoal
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ok so we dont have the y

pearl sand
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no so we dont have the x

floral shoal
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okok

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so the x would be 4 square - y square

pearl sand
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i need to think

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can we ignore the solutions formula

floral shoal
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yes

pearl sand
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it just doesnt make sense to me

floral shoal
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try something

pearl sand
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Ok I read your French Solution so they substituted

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why didnt you tell me

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$\int_{y=-h}^{y=+h} \pi(R^2-y^2-r^2)dy$

floral shoal
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what do u mean

civic schoonerBOT
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adonhs

pearl sand
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On remplace bien sur x² = R² - y²

floral shoal
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are u french

pearl sand
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no i am guy who used translator

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Let's rewrite the bounds too

floral shoal
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where did u find the solution

pearl sand
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$\int_{y=-\sqrt{R^2-r^2}}^{y=+\sqrt{R^2-r^2}} \pi(R^2-y^2-r^2)dy$

civic schoonerBOT
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adonhs

pearl sand
floral shoal
pearl sand
floral shoal
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I dont have a teacher

pearl sand
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ok main character

floral shoal
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my friend its the same thing

pearl sand
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mon frere ok

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So R = 4 and r = 1

floral shoal
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and its equal 20\sqrt{15}\pi

pearl sand
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$I = \int_{y=-\sqrt{15}}^{y=+\sqrt{15}} \pi(16-y^2-1)dy = \pi \int_{y=-\sqrt{15}}^{y=+\sqrt{15}}(15-y^2)dy \ \= 15\pi y - \frac{\pi}{3}y^3 \bigg |_{-\sqrt{15}}^{\sqrt{15}}$

civic schoonerBOT
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adonhs

pearl sand
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Is there a mistake?

floral shoal
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its 20 But ty sir

pearl sand
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thats y im asking

floral shoal
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?

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its y there

pearl sand
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$=15\pi \sqrt{15}- \frac{\pi}{3}(\sqrt{15})^3 - 15\pi (-\sqrt{15}) + \frac{\pi}{3}(-\sqrt{15})^3$

civic schoonerBOT
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adonhs

pearl sand
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$=20\pi\sqrt{15}$

civic schoonerBOT
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adonhs

pearl sand
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I found the mistake

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there was a minus instead of plus

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$=20\pi\sqrt{15} \approx 243.346$

civic schoonerBOT
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adonhs

pearl sand
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which is insane

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if you did this with a sphere and cylinder formula you get

floral shoal
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Exactly thank you sir

pearl sand
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,w V = 4/3pi4^3-pi1^2*8

civic schoonerBOT
pearl sand
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242.94

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it's really close

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bonjour gojo

floral shoal
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bonjour XD

pearl sand
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oh i meant merci