#polynomial function help
26 messages · Page 1 of 1 (latest)
All i know is the
Roots are -3,2,6
i got -20(x+3)(x-2)^2(x-6)
y=q(x-a)(x-b)(x-c), plug in the values for a b and c, and the point (-2, -32) and you should b able to get the answer.
That’s not working
Hold on, let me try.
It’s a quartic.
So it should be y=(x-a)(x-b)(x-c)(x-d)
Idk how I overlooked that
Thats what i did, is q=-20?
i got a negative number which is weird because the function is positive
It’s a quartic
it definitely shouldn’t be -20
Btw even if it was a cubic it would be 1, not -20
y=1/4(x+3)(x-2)^2(x-6) ?

.solved