#Maxima and Minima
31 messages · Page 1 of 1 (latest)
@toxic tiger
resending so i can see full img
f'(x) is undefined wherever:
f(x)abruptly changes direction. For example,f(x) = |x|has an undefined derivative atx = 0.f(x)is undefined. For example,f(x) = 1/xhas an undefined derivative atx = 0.
one sec
@toxic tiger i havent watched this video, but according to the title it will help you out https://youtu.be/xuAiQOzIkWY
Courses on Khan Academy are always 100% free. Start practicing—and saving your progress—now: https://www.khanacademy.org/math/ap-calculus-ab/ab-differentiation-1-new/ab-2-4/v/differentiability
Defining differentiability and getting an intuition for the relationship between differentiability and continuity.
Practice this lesson yourself on Kha...
if u dont have the time to watch that entire video, i can also help
ya ofc
do you understand these two rules?
ok, so which ones apply to this problem
hint: ||only one applies to this problem. not both.||
ya perfect
in this case, i see that the function does not reach __+__3. where does the function stop on both sides?
we'll get to local minimums/maximums later
yep
in this case, the y-coordinate doesn't matter but its not problematic that you found them
so do you know how to write the interval notation for where f(x) is undefined?
not 1
youre referencing the y-values, which are completely useless right now
this is very close, but (-2.5,∞) should come before (2.5,∞)
So f(x) is undefined on (-2.5,∞) U (2.5,∞)
If f(x) = √x, then f'(x) is undefined at x = 0.
can you see how that applies to this problem
?
what im trying to get at is: f(x) stops at x = 2.5, so f'(x) is undefined at 2.5
so your answer should use [ instead of ( next to 2.5
make sure to do the same for -2.5
the part before the U is wrong
it should be (-oo, -2.5]