#Maxima and Minima

31 messages · Page 1 of 1 (latest)

fresh fogBOT
dreamy galleon
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@toxic tiger

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resending so i can see full img

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f'(x) is undefined wherever:

  • f(x) abruptly changes direction. For example, f(x) = |x| has an undefined derivative at x = 0.
  • f(x) is undefined. For example, f(x) = 1/x has an undefined derivative at x = 0.
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one sec

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@toxic tiger i havent watched this video, but according to the title it will help you out https://youtu.be/xuAiQOzIkWY

Courses on Khan Academy are always 100% free. Start practicing—and saving your progress—now: https://www.khanacademy.org/math/ap-calculus-ab/ab-differentiation-1-new/ab-2-4/v/differentiability

Defining differentiability and getting an intuition for the relationship between differentiability and continuity.

Practice this lesson yourself on Kha...

▶ Play video
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if u dont have the time to watch that entire video, i can also help

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ya ofc

dreamy galleon
dreamy galleon
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hint: ||only one applies to this problem. not both.||

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ya perfect

dreamy galleon
# dreamy galleon

in this case, i see that the function does not reach __+__3. where does the function stop on both sides?

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we'll get to local minimums/maximums later

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yep

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in this case, the y-coordinate doesn't matter but its not problematic that you found them

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so do you know how to write the interval notation for where f(x) is undefined?

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not 1

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youre referencing the y-values, which are completely useless right now

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this is very close, but (-2.5,∞) should come before (2.5,∞)

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So f(x) is undefined on (-2.5,∞) U (2.5,∞)

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If f(x) = √x, then f'(x) is undefined at x = 0.

dreamy galleon
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?

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what im trying to get at is: f(x) stops at x = 2.5, so f'(x) is undefined at 2.5

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so your answer should use [ instead of ( next to 2.5

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make sure to do the same for -2.5

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the part before the U is wrong

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it should be (-oo, -2.5]