#I need help with this question
near breachBOT
runic mica
Get the -1 to the other side and square both sides
runic mica
Can you sned a picture of you work?
nova prism
add 1 to the other side to make it √3x=1+(√1+x).
Then, Square both sides so it becomes 3x=(1+√1+x)(1+√1+x)
now try to solve: (1+√1+x)(1+√1+x)
dapper cipher
The question is telling me to use binomial formula
nova prism
oh I'm not sure then. Sorry
runic mica
its equal because -1 and square root of posative 1 is -1*-1
runic mica
The question is telling me to use binomial formula
What is binomial formula?
dapper cipher
Didn't u post that yesterday?
Oh damn I sent wrong pic
There we go
thats the questions
quick drum
you can do the same approach 😂
runic mica
Get the 2x and sqrt(4x+1) to the other sides
dapper cipher
I did but I didnt get the answer
runic mica
Then square both sides and you are left with a quadratic
runic mica
Yes and by squaring you use the binomial formula
dapper cipher
oh
runic mica
I did but I didnt get the answer
Can you show how you did it?
dapper cipher
Ok this is what I did
runic mica
Because then I know where you went wrong
runic mica
the quadratic formulas -b+-the square root of b squared minus 4ac, all over 2a
dapper cipher
the quadratic formulas -b+-the square root of b squared minus 4ac, all over 2a
The quesstion is telling me to use binomial formula
runic mica
I want to use quadratic >:t
runic mica
Sorry but there are a lot of thing wrong here
dapper cipher
Sorry but there are a lot of thing wrong here
Yeah what should i do
Im not really good with square roots
Thats why lol
runic mica
It should be $7-2x=\sqrt{4x+1} \ 49-28x+4x^2=4x+1 \ 4x^2-32x+48=0 \ x^2-8x+12=0 \ (x-6)(x-2)=0 \ x=6 \lor x=2$
proud sageBOT
Ryanstaal2006
dapper cipher
So you switch 2x
runic mica
Yes
runic mica
Because when you have something like this with a constant, a term with x, and a square root containg x you want the square root alone so when you square you get rid of the square root and don't get another term with a square root
dapper cipher
So for a question like this
What do you do?
The answer is 3
But how do you find that
runic mica
Because when you have $7-\sqrt{4x+1}=2x$ and you square both sides you get $49-14\sqrt{4x+1}+4x+1=4x^2$ so you still have the square root and you don't want that
proud sageBOT
Ryanstaal2006
dapper cipher
**Ryanstaal2006**
I see
runic mica
$ \sqrt{3x}-1=\sqrt{1+x} \\ 3x-2\sqrt{3x}+1=1+x \ 2x=2\sqrt{3x} \ x=\sqrt{3x}\ x^2=3x \ x=0\lor x=3$ checking gives that x=0 doesn't work and x=3 does
$\sqrt{3x}-1=\sqrt{1+x}
\ 3x-2\sqrt{3x}+1=1+x
\ 2x=2\sqrt{3x}
\ x=\sqrt{3x}
\ x^2=3x
\ x=0\lor x=3 $
dapper cipher
Its not working
runic mica
