Displacement question

[south junco]

Somebody explain the highlighted part...? I'm missing something

[fluid hatch]

that's the distance displacement any particle along the rope on top of the pulley

at the end (s = 0), the string will be right angled

,tikz
\draw[->] (0,0) |- ++ (3, 1.5) node [above right]{$\vec F$};
\begin{scope}[blue!40]
\node[anchor=east] at (-0.5, 0.75) {1.5 m};
\draw[<->] (-0.3, 0) -- ++(0, 1.5);
\end{scope}
\node[draw] at (current bounding box.north) {$s = 0$};

[tall coral]

vin100

[south junco]

yeah okay but why do we subtract the hypotenuse from the height

little confused about that

[fluid hatch]

we can assume that the string is always tight

so the distance travelled by any particle along the string is the same

so that the distance travelled by any particle along the string above the pulley is the same

since the string is tight, we have a "conservation of length of the rope"

decrease in the length of rope below the pulley = increase in the length of rope above the pulley

[south junco]

oooooh yeeeeaaaah

[south junco]

i am so stupid to not have seen that LOL

thank you!

thats what i was missing

[fluid hatch]

every master starts as a newbie

[south junco]

.solved