#completing the square
7 messages · Page 1 of 1 (latest)
You did a minor mistake
Also after factoring out the 2, you focus now on the inner term
$\(x^2-\frac{7}{2}x+2)$
adonhs
When you add $\frac{49}{16}$ you have to also subtract it, otherwise you lose the equality of your previous terms.
So basically you gotta do:
$\2\bigg(\bigg(x^2 - \frac{7}{2}x + \frac{49}{16}\bigg) + 2 - \frac{49}{16}\bigg)\$
$\ = 2\bigg(\bigg(x - \frac{7}{4}\bigg)^2 + 2 - \frac{49}{16}\bigg)\$
$\ = 2\bigg(\bigg(x - \frac{7}{4}\bigg)^2 - \frac{17}{16}\bigg)\$
And now just multiply the 2 back in.
$\$Basically, you continue working within the brackets of your term.
adonhs