#Tricky Question
86 messages · Page 1 of 1 (latest)
$\begin{bmatrix} x_1 & y_1 \ x_2 & y_2 \ ax_1 + bx_2 & ay_1 + by_2 \end{bmatrix}$
hmm
lebesgue
let me think
can you do it without using linear algebra tricks
but it's alright if you want to
I'm supposed to solve this without linear algebra or matrix stuff
oh yeah dw abt that its easier for me to think in matrix terms
ill convert it back to algebra
i dont have a pen n paper w me now so
thanks!
at the gym
yeah it's cool dw
its definitely yes
but im still thinking how to express equation 1 using a and b
$x_3 = ax_1 + bx_2$
lebesgue
$x_1 = \frac{x_3 - bx_2}{a}$
lebesgue
$c = \frac{-b}{a}$
lebesgue
$d = \frac{1}{a}$
lebesgue
how were you able to come up with this?
lebesgue
okay lets restart, I think my explanation is pretty messy
nah it's fine bro I'm just doing it in my head
lebesgue
let $y = dy_1 + ey_2 + fy_3 + ...$
lebesgue
let $z = gz_1 + hz_2 + iz_3 + ...$
lebesgue
if $ax + by = z$
lebesgue
then $x = \frac{-b}{a}y + \frac{1}{a}z$
lebesgue
if $x = cy + dz$
lebesgue
then $c = \frac{-b}{a} \text{ and } d = \frac{1}{a}$
lebesgue
@nova fox does that help?
yep it does
I'm just trying to figure it out right here cause I don't have a pen and paper too
fair haha
but when it comes to linear equations
matrix is the way to go
the whole field is designed to solve linear equations after all
yeah but I'd like to do it without doing that
I'll get to it during college
seems like you study cs
I'll also be taking cs so it's bound to happen
basically 60% stats, 30% cs and 10% maths
would you say that ds is a good course to take?
I'm also thinking of taking it
I'll get back to the problem when I wake up tomorrow, I wasn't really planning on finishing it right now haha
because I was about to sleep
just questioned it here so I can get back into it tomorrow with some guide already
depends on the university tbh
it is an emerging field, if ur into AI or quant then its a good course to take
I'm still confused
oh i get it now
now that uh
wait im thinking
what makes the answer to letter a yes?
are these the constants that when multiplied to equation 2 and 3 equal to equation 1?
and they're also just the c and d in terms of a and b right?