HELP PLS

[swift peak]

umm, iirc, this limit expression is the definition for differentiation of acosa

ye

[zenith nexus]

yep

$f'(x) = \lim_{h \rightarrow 0} \frac{f(x+h) -f(x)}{h}$

[edgy belfry]

lebesgue

[zenith nexus]

in this case f(x) is xcos(x)

and its evaluated at a

so f'(a)

[wraith turtle]

so try to use L'hospital rule

i.e. differentiate numerator and denominator independently

wrt h

and then put h = 0

so thats your answer

[formal jewel]

yeah or first principles

as this is a direct application of that

[wraith turtle]

like if $\lim_x\to0 \frac{x^2}{x} = \lim_x\to0 \frac{\frac{d(x^2)}{dx}}{\frac{d(x)}{dx}} = \lim_x\to0 \frac{2x}{1} \implies 0$

[edgy belfry]

ᴰᴱᴬᴰ ★ ᴋɪʟʟᴇʀ ⁰⁴

[formal jewel]

btw how to use texit

it makes things sm more neater

[zenith nexus]

learn latex

[dusty plinth]

oo

i did this

can yall check if its correct?

@zenith nexus

ignoring

the

thingy

i did wrong

[unreal herald]

looks correct