#I need help with B, C, and D
47 messages · Page 1 of 1 (latest)
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
Are you still there?
just in case
case b its an excercise with fractional exponents
on case c u can simplify the first parenthesis as (a-b)^3
and the right one can be factored in terms of (a-b)
case d u can try to simplify the fraction using difference of squares
yo @drifting gale is the answer for C)
-(a-b)^2
if it is
then simplify first parentehsis as (a-b) the whole cube
then rearrange (b-a) as -(a-b)
take (a-b) as t
solve it
in the end you get -t^2
in c part
we can see that the first term is (a-b)^3
now open the brackets of second term
cubic term will get cancelled
only quadratic term is left
Im still here
try to follow these steps
Ok ill try
It is
then do the steps i have instructed below and send a pic
il check whether the working is correct or not
ok so
let's start with the first parentheses shall we
the expression inside the bracket is the expression for (a-b) ^3
once you do that
rearrange (b-a) as - (a-b)
then let the term (a-b) = some variable t
from there it's simple
try it
How did you get (a-b)^3
Thats my question firstly
its because its an Remarkable identity