#Solve for x, y, and x^3
60 messages · Page 1 of 1 (latest)
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
show your progress
it's just a bunch of scratches
i doubt you'll understand what I've written because it's so unorganized
from $\frac{y}{3} = \frac{x}{y}$
artemetra
artemetra
$x = \frac{y^2}{3}$
artemetra
substitute that into $\frac{2}{x} = \frac{y}{3}$
artemetra
$\frac{6}{y^2} = \frac{y}{3}$
artemetra
$\frac{y^3}{3} = 6$
artemetra
and continue from there :)
actually!
there's an even easier way
if you only need to determine x^3
from $\frac{2}{x}=\frac{x}{y}$
artemetra
you get that $y=\frac{x^2}{2}$
artemetra
and substitute that into $\frac{2}{x} = \frac{y}{3}$
artemetra
$\frac{2}{x} = \frac{x^2}{6}$
artemetra
thank you so much!
I'll try to solve it on my own now
multiplying y to both sides of this
would make it equal to
xy = 6?
to make it easier
you are like 2 steps away
but also your problem doesn't require you to solve for y
it only needs x^3
if you go this way it's much much easier
hold on bro
my family needs to go to church for christmas reasons I'll continue this when I go home
no worries
12
no problem
.solved