#Help find integral
102 messages · Page 1 of 1 (latest)
I started the problem by adding 5 and -3 to 2 what do i do after? Shouldn't integral of a to -a be 2?
@severe ice
Reading the problem, S[x] is odd, R[x] is even.
Is this not how I start it?
Because it goes from -a to 0 then the other goes from 0 to a so wouldn’t I set it equal to integral of -a to a?
Given each area
you have to have the same function in each integral tho
what you wrote here doesn't work at all
Yep, can do it that way, just take care of the odd/even functions and their symmetries
$$\int_{-a}^{a} (2S(x) - R(x))\dd{x} = \int_{-a}^0 (2S(x) - R(x))\dd{x} + \int_{0}^a (2S(x) - R(x))\dd{x}$$
aPlatypus
then you can split it further if you want
and then i would substitue the given areas?
yeah
how would i get the variable a out of it? Is there an antiderivative I have to do
are you trying to solve the integrals without known functions for R[x] and S[x]?
and use the oddness / evenness of R and S to get the areas that you don't know already
yes
you're misusing the rule
that's the problem
$$\int_a^b f(x) = \int_a^c f(x) + \int_c^b f(x)$$
aPlatypus
where is the +3 from?
i never understood that part either
that was a reused study guide its not my writing
someone forgot to type it in the question lol
that's the only thing I can see
that's what I was wondering. No way I got any 'a' in my approaches without that +3.
oh shoot nvm i remember my substitute saying something like that
lol
yeah the problem was mistyped
ty
you've got it from there?
ill let yall know if i dont
but i get the process now
and i see where i was initially stuck on
Here's the symmetry the others were talking about earlier, just in case.
so since i missed the 3, would there also be a +3 in each integral now too?
yea
i cant find the missing areas now
they give us two integrals, let's pick one and focus on that. Do you want to work on S[x] or R[x]?
S(x)
we are given S[x] is odd and that the integral from 0 to a of S[x] is equal to -3
yes
knowing S[x] is odd, this gives us a way to determine the integral of S[x] from -a to 0
how is that
let's try an example. Let's take f[x] = x and integrate f[x] from 0 to 1
This is how the figure looks
so would i draw it out and find the area from there?
that's one way to do it 🙂
If you know the area from x = 0 to x = 1, what do you think the area is from x = -1 to x = 0?
yes, exactly
They're giving you a value for S[x] integral for x = 0 to x = a. What do you think is the value of S[x] integral when we use x = -a to x = 0?
Why isn't this?
because the pink part was missing +3 in the integral
so would -a to 0 of S(x) be positive 3?
yes
@proven python for R(x) would it be double then?
very good
Here is an even function from x = -2 to x = +2
If we folded this across the y-axis (like closing a spiral notebook), the two sides would match up
finish it there guys
Since the integral from -a - 0 is even, it is equal to the integral from 0 to A
Here is a graph of another even function, this time from -pi to pi:
Just like Joaco indicates, the integral from -a to 0 of this function is the same number as integrating from 0 to a
If folding with imagination is difficult (usually is for me). You can sketch an even function on paper and fold that 🙂
and just to clarify, for the 3 integral would it worklike an even function too sort of?
3a on both sides
yes
ye thats what i drew
nice