#I have a word problem question
82 messages · Page 1 of 1 (latest)
Is it known that b and c had nothing initially?
If so, then
b has (1/3)a
And
c has (1/5)a
You should be able to form an algebraic expression with this and solve for a then.
Yes
What about the 28 less
Would it be 1/5a=1/3a+28=a
@versed loom
<@&286206848099549185> is this correct
Nah nah
b has 28 more. So, you'd have to add 28 to 1/5a.
Only then will they be equal
And also. You don't equate them to a directly. You just solve for a.
So, the =a here won't come when you're solving the eq
Then how would I do it
You did
1/5a = 1/3a + 28.
But this is the equation when c has 28 more.
In the given question, c has 28 less
So, how do you think your eq would change?
Depends really
a just has to be an amount
And an amount can take decimals too
So, it depends
Wait it would be -28
I haven't solved it, so idk. But it might turn out to be a whole number too
Correct
Then you would divide both sides with -28?
Now try solving
$\frac{1}{5}\cdot a = \frac{1}{3}\cdot a-28$
Galactic Fur
The bots having a stroke
This is similar to solving
5x = 3x - 28
Wut's the value of x in this case?
I mean, if you know how to solve an algebraic expression, you can go straight to solving the main eq of the problem
Wut's the value you get for a?
Now try solving the same way for this eq
Wut's the value for a you get?
It would be -2/15x=-28
You're welcome!!
Everything is actually just normal algebra.
Wut you can do is, spend some time reading and understanding the word problem, and the try to convert it to normal algebra
It'll make it much easier for you
wdym?
Nah. It'd be in rupees for me
Oh
I'm trying to convert to your currency what R210 would be
Which country's is that?
It's this much in your currency
Also it's south african rand
Is that alotin your currency
Is that alot for you
Not really.
Depends on who you ask.
You ask me, a 20y/o, I'd say no.
You give this to some school kid, he'll experience heaven
@versed loom how do I make this solved
.solved
