#Circle Area with percentages
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The question says: 2/3 of A is drawn. 60% of C is also drawn, so what is B?
I cant seem to figure it out?
<@&286206848099549185>
Let
A1 = area of the little circle
A2 = area of the big circle (including the little one)
From A you know that 2/3*A2 is equal to A1
From C you know that the disk is cut out with proportion 60%-40%
So B is 6/10 of the little circle. So B = 2/3*6/10*A2
Im pretty sure none of those answers are correct
What makes you say that
I solved it, my math teacher helped me. 2/3 times 6/10 = 12/30 = 2/5
What Farah said is wrong.
I didnt mean yours.