Guys help to solve this problem

[fierce magnet]

R(10) = R(2*5)

So R(10) will carry the prime factors of R(2) and R(5)

Could add some to the list

R(10^9) = R(2^9 * 5^9) will have the prime factors of R(2), R(4). R(5), R(10), .... R(2^k * 5^q) ....

[brittle needle]

okey so what do you mean by 2 at k and 5 at q

so for example i need to find first 2 prime factors of 10 at power of 9

so what i can do

[fierce magnet]

So 2 doesn't divide it

3 also doesn't

Hm

Are you allowed to use a computer?

[brittle needle]

yea bro actually now i am not solving math problem i am doing hacker rank contest so to solve this problem i need to create algorithms but i don't know how to solve it in math to create algorithms

[brittle needle]

wdym

[brittle needle]

Guys someone can help