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the problem in the very middle, I dont know how to do this
try to open it
∫ t dt + ∫ sin t dt
[t^2/2 - cos t ]
uppur limit = 1
lolwer limit = cos x
so it becomes 1/2 + cos 1 - cos ^2 x/2 + cos cosx
o yea i got it
thank you