#can someone help me understand “ If a + b = 0 the b = -a AND a = -b” ?
31 messages · Page 1 of 1 (latest)
I think everything you stated is correct
Like the things you said they are related so there is not really confusion... looking at the proof yes it looks like additive invere but it is more proving the statement that if
a + b = 0 is true then
a = -b or b = -a follows/is also true
But without more context and judging by the picture, you may assume that it can have to do with additive inverse
But then if that’s the case
What if I did -b -a
Wouldn’t that turn to negative b minus a?
Or is it only -b + a or -a + b
wdym
a + b = 0
a = -b or b = -a
If a = -b
(-b) + b = 0 TRUE
If b = -a
a + (-a) = 0 TRUE
Hence two answers (a = -b or b = -a)
If you did -b - a = 0 the proof still works
I'm assuming a and b are real numbers
So a + b = 0 is enough no need to do -b - a = 0
Otherwise I dont get your question tho
a = -b and b= -a are actually the same equation, when distributivaty applies. If a + b = 0, a and b are just iverses of each other.
I thought it was saying it could apply if they where both negatives
Well I figured in meant they where just inverses I was just a little confused
Now that I think about it yea that makes sense
I was just confused but I think it’s just talking about additive inverses
Cause I mean at the end of the day if a + b = 0 then that implies that a and b are just inverse of each other right?
exactly
Thanks for the help how do I mark it as solved
Post marked as solved by @proper monolith.
Use .unsolved if this was a mistake.
a+b=0 and -a-b=0 are actually the same equation, because a and b are inverses of each other.