I'm following 3Blue1Brown's Essence of Calculus series, and near the end of Chapter 3; he proposes the following question:
Imagine a rectangle in 2 dimensions, whose area is 1. Let's say that its width is x; the height has to be 1/x to maintain that area of 1.
For the derivative, imagine nudging up that value of x by some tiny amount, dx. How must the height of this rectangle change so that the area of the rectangle stays as 1? That is, increasing the width by dx adds some new area to the "right". So, the rectangle must decrease in height by some d(1/x); so the area lost off that top cancels out the area gained. You should think of that d(1/x) as some negative amount, since it's decreasing the height of the rectangle.
Now, try reasoning out the slope ( d(1/x) / dx ) is. Compare what you got instead of what you would have gotten if you blindly applied the power rule ( nx^n-1)
I've attached a visualisation of this problem and my attempt at solving it. I've only gotten as far as x+dx^2 - x*dx.
(Sorry for the sloppy lines, don't have any graph paper left)
reaction for more information.