#Inequality for complex numbers
13 messages · Page 1 of 1 (latest)
And x_1, x_2, etc. are all complex numbers?
$\bigg(\sum_{i=1} |x_i|\bigg)^{\frac{1}{2}} \leq \sum_{i=1} |x_i|^{\frac{1}{2}}\$
where $\sum_{i=1} x_i = x_1 + x_2 + ... + x_k$
adonhs
using the fact that sqrt is concave you can show an even stronger inequality
@vale edge
now as for intuition
¯_(ツ)_/¯
it's not like it's even specific to modules of complex numbers or anything
replace your |x_i| and just have x_i positive real numbers instead and it still works fine
Yes
Hmm ok. Thinking this way is clearer. I imagine using indution is a way to go, too