anyone knows how to do this

[autumn lark]

A young trader receives £7509 a year interest from investing £60,000 in two bonds. One bond pays 7% and the other pays 20%. How much is invested in each bond? State your answers to the nearest pence.

[autumn lark]

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[worthy cradle]

lemme try to do it first

[autumn lark]

Ok

[worthy cradle]

it might take sometime please wait

denote the amount that we investe in the 7% bond as
60,000
x, and the amount invested in the 20% bond as
60,000 − 60,000−x since the total investment is £60,000.

and the interest from the 7% thingy is 0.07x and the interesst from the 20% is gonna be calculate by 0.20 x (60,000 - x)

[autumn lark]

OK is that it?

[worthy cradle]

then the total interest we recieved is 7509 bond -> set up equations
0.07x + 0.20 x (60,000−x) = 7509

then u solve x

the amount invested in the 7% bond is approximately £26,846.15, and the amount invested in the 20% bond is 60,000 - 26,846.15 = 33,154 -> 33,153.8
therefore, the trader has invested approximately £26,846.15 in the 7% bond and £33,153.85 in the 20% bond.

thats it

[autumn lark]

Thanks

[autumn lark]

@worthy cradle sorry one more thing to solve x did u put it on a calculator or did it urself

[worthy cradle]

u should do it urself

thats the reason i cant tell u answer directly too

u can ask if u cant do it, ill tell how

[autumn lark]

Ye could you help me on thag

[worthy cradle]

um sure

first u need to do 0.07x + 12,000 - 0.20x = 7509

then its gonna be like this -0.13x = -3491
then divide by -0.13 then ull get the X by

x = -3491/-0.13 = approximately 26,846.15