graphs

[stiff sedge]

I need help with bottom

[stiff sedge]

I understand most of it but the bottom

[blissful falcon]

the roots are -1 and 3.

So calculating the point between them: (-1 + 3) / 2 = 1

So plugging in x = 1 into your function f(x) will give you the according y value for the bottom

[stiff sedge]

So the roots are also know as values

?

[blissful falcon]

what do u mean

[stiff sedge]

The bottom where it says uh

The values

[stiff sedge]

Here

The values of x

That part is tripping me out

[blissful falcon]

You mean the table?

[stiff sedge]

No no

The very bottom

[blissful falcon]

The minimum?

[stiff sedge]

Where it says thr value of x for which x²

[blissful falcon]

You mean this equation:

$\ x^2-2x-3 = x-3$?

[stiff sedge]

Yes

[shy mesa]

adonhs

[blissful falcon]

You need to solve for x

[stiff sedge]

Wdym

So then x is 2?

[blissful falcon]

Transform equation in such a way that x is alone and the other side is a number

[stiff sedge]

I still don't get

[blissful falcon]

$\x^2-2x-3 = x-3 \quad \bigg | -(x-3)\$

$\ \Rightarrow x^2-2x-3 -(x-3) = 0\$

$\ \Rightarrow x^2 -2x -x -3 +3 = 0\$

$\ \Rightarrow x^2-3x = 0 \$

$\ \Rightarrow x(x-3) = 0 \$

Use zero product property:

$\ \Rightarrow x_1 = 0$ and $x_2 = 3$

[stiff sedge]

Hmmmm

[shy mesa]

adonhs

[stiff sedge]

X=0

How is that

[blissful falcon]

Plug it in for x and you will see the outcome is 0

[stiff sedge]

Wait lemme check

[blissful falcon]

$0 \cdot (0 - 3) = 0$

[shy mesa]

adonhs

[stiff sedge]

Oh

The x cancels the x

Leaving 0

And x cant go in to 3

[blissful falcon]

Now try x = 3

[blissful falcon]

You can see it also like that 0 times any other number is 0

[stiff sedge]

Your right your right

Thanks adonhs

How do I end this now

[blissful falcon]

what

[stiff sedge]

Like end

This

Channel

[blissful falcon]

.solved

[strong flume]

Solved

Post marked as solved by @blissful falcon.

Use .unsolved if this was a mistake.

[blissful falcon]

lol

[stiff sedge]

Oh