How do I Transform an Equation to a Quadratic Equation?

[small drift]

what method do i use?

[small drift]

the one on the top is the first question

[patent warren]

simply take the lcm bro

$\frac{x+2(3x+2)}{(3x+2)(x)} = -2$

[cunning needle]

Aditya gamer

[patent warren]

so :
$x+6x+4 = -2(3x^2+2x)$

[cunning needle]

Aditya gamer

[patent warren]

$7x+4 = -6x^2-4x$

[cunning needle]

Aditya gamer

[small drift]

isn't it like 2, and x - 3 and you multiply them to x + 3 and x, and if 2 is multiplied to its own number it gets cancelled out, same to (x - 3)

[small drift]

nice

[small drift]

then we simplify then transpose? @patent warren

[patent warren]

please wait

[patent warren]

yes
$6x^2+11x+4 = 0$

[cunning needle]

Aditya gamer

[small drift]

nice

how about the second?

[patent warren]

what?

[small drift]

the 2nd one here

2nd question

[patent warren]

use the same way

and try on your own

If you get any problem then I will help

I am here for the next 30 minutes

@small drift

[small drift]

okay

,help

[cunning needle]

I can't DM you! Do you have DMs disabled?

Nov 23, 2023, 2:03 PM

[small drift]

,help

[cunning needle]

A brief description and guide on how to use me was sent to your DMs!
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[patent warren]

@small drift ??

Just send the photo

[small drift]

how do i use this bot

okay

[patent warren]

@small drift ..

[small drift]

this?

@patent warren

[patent warren]

You got one thing wrong let me write it

[small drift]

okay

[patent warren]

$\frac{x+3}{2} - \frac{x}{x-3} = 4$ = $\frac{(x+3)(x-3) -2x}{2(x-3)}$

[cunning needle]

Aditya gamer

[small drift]

whats next

[patent warren]

Yeah then

$\frac{x^2-9-2x}{2x-6} = 4$ which is $x^2-2x-9 = 4(2x-6)$

[cunning needle]

Aditya gamer

[small drift]

then we simplify yea?

[patent warren]

$x^2-2x-9 = 8x-24$ which is $x^2-10x+15 = 0$

[patent warren]

yeah

no no wait

[small drift]

• -9 - 24?

[patent warren]

Yeah this will be correct

[cunning needle]

Aditya gamer

[small drift]

oh nice

[patent warren]

@small drift this is the final answer

yeah

[small drift]

thanks alot

do u happen to know

if khan academy

has a lesson on this

[patent warren]

anything you did not understand?

Let me see

[small drift]

im good thanks

[small drift]

whats a good alternative to khan academy, if they dont have the lesson

[patent warren]

I think geeksforgeeks as I understood whole quadratic equations from them

[small drift]

.solved

[pulsar edge]

Solved

Post marked as solved by @small drift.

Use .unsolved if this was a mistake.

[small drift]

ty again!