#maths I'm dumb
208 messages · Page 1 of 1 (latest)
which task do you need help with exactly?
Most
what have you done?
Number 5
Do you wanna begin with 1)
Why not
Ok did you notice that these are mixed fractions
$5\frac{1}{2} - 1\frac{2}{7}$
adonhs
Do you even know what mixed fractions are?
bruh
Say you have a fraction like:
$\ a\frac{b}{c} = a + \frac{b}{c}$
adonhs
This is basically it
It's a shorter way to describe the sum of a whole number with a fraction
Oh
Is this information enough for you to evaluate it now?
Yeah I think
Then we can go to 2) or?
Yeah we can
Ok did you read task 2)?
a house in 2020 costs 250.000 $
each year the prices increases by 4 %
Yes
what is the prices in 2022
so we wanna know the price after 2 years
2020: 250.000 $
2021: ?
we wanna calculate the interest
adonhs
Then our new capital is:
$\ capital_{new} = I + capital_{previous}$
adonhs
Oh btw I done number 3
$\ I_{2021} = \frac{250000\cdot 4}{100} = 10000$
adonhs
$\capital_{2021} = capital_{2020} + I_{2021}$
adonhs
So answer is 270.000
Now quite
Youu need to do the whole procedure with the capital of 2021 for capital 2022
$\ I_{2022} = \frac{260000\cdot 4}{100} = 10400$
adonhs
$\capital_{2022} = capital_{2021} + I_{2022}$
adonhs
270.400
$\capital_{2022} = 260000+10400 = 270400$
adonhs
You have to calculate the interest rate on the new price again for each year, not for the one in beginning
what's your result in number 3?
@torpid lion
I got something totally different
$V_{cyl} = \pi \cdot r^2 \cdot h
\ V_{sph} = \frac{4}{3} \cdot \pi \cdot r^3$
adonhs
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This is thing where need to do 3.14
you mean for pi? yeah you could do that
What can you say about the sphere
What happened with the sphere?
No I don't mean the description of the formula
I mean if you look at the picture
of your shape
You can see a cylinder and a sphere but what happened to the sphere?
The 70 cm gets cut off
what do you mean exactly
What I am talking about is the sphere is cut in half
this is important
Oh shit poor sphere
So what happens to the volume of the sphere if it's cut in half?
It get ÷ by 2
very well done
So the whole volume V consists of:
$\ V = \frac{1}{2}V_{sph} + V_{cyl}$
adonhs
Now let's calculate the poor sphere's volume first
Right okay
$\frac{1}{2}V_{sph} = \frac{4}{3} \cdot \pi \cdot r^3 \cdot \frac{1}{2}$
adonhs
what is the the radius of the sphere?
70
NOPE
24
that's the diameter
Wait 2 secs
if 24 is the diameter what was the radius of the sphere
35? 70? 1? 100? 5millon?
what did you do in that time hahaha
Memorize this: The radius is always half the the diameter
The sphere is 24 cm long basically (diamter) so the radius is 12
Oh fuck
That's basically all we need so plugging in we get:
$\ \frac{1}{2}V_{sph} = \frac{4}{3} \cdot \pi \cdot (12)^3 \cdot \frac{1}{2} = 1152\pi [cm^3]$
adonhs
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Anyway that's estimated:
$\ \frac{1}{2}V_{sph} ≈ 3619.11 [cm^3]$
adonhs
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Now we need the volume of the cylinder
what's the radius and the height of the cylinder?
Oh shit
12 and 70 or 35 or 100millon fuck knows
I hate geometry
The whole shade is 70 cm high (including the poor sphere) but we want just the height of cylinder
you can do this
SO there must be a difference
To get the actual height
of cylinder
How long is the sphere?
vertically speaking
I'm sooo stupid I have been thinking the sphere was the cylinder 70
no problem
you are not stupid get that shit out of your head
Right
If we subtract the height of the sphere (vertically speaking) from the whole height 70 with what height are we left
70 is the whole thing take away the poor sphere
how much height is left
0 doesnt make sense because other wise the cylinder would not have a height and would not exist thus it's 58 how come?
Because I done 12 take away 70
perfect, see you are not "stupid"
Now we have the height of cylinder h = 58 and the radius r = 12 plugging them in we get:
$\V_{cyl} = \pi \cdot (12cm)^2 \cdot 58cm = 8352\pi [cm^3]$
adonhs
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$\V_{cyl} ≈ 26238.58 [cm^3]$
adonhs
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Now what is the last and final step to do?
Add them
29,857.69cm3
Task 4 is I think about proportions
3 ton food for 350 sheeps will last for 18 days
Now we have 100 sheep additionally, thus 450 sheeps in total
We know 350 sheeps need 18 days
Yes
So if we add more sheeps do you think the food will be gone sooner or later?
correct but dont be too specific
we would need to calculate how long the food would last for one sheep
Right
so 3 tons of food would basically last for one sheep 350 * 18 = 6300 days
Right
because the farmer has 350 sheeps / day
14 days?
if for one sheep 3 tons of food last 6300 days
then for 450 sheeps it will last: 14 days
yes
Nice is that it
Mmmmmm
Is their more to question because if we are ill sent the last maths question
i dont think so that there is more
Yes
baby milkpowder is sold in 900 gramms packs
what row of the tableau should we consider?
sorry i meant row haha
Oh shit I done the wrong one lol
Oh shit shoot them
1 scoop = 4.5 g
8 scopps = 4.5g * 8 = 36 grams
so for one milk 36 grams are wasted
so for 4 milks = 36 * 4 gramms = 144 grams are wasted per day
so do you think a 900 gramm pack will last for one week?
Oh no bomb them
nah hell nah that baby will starve to death
144 gramms * 7 = 1008 grams of powder is needed for one week
but we only have 900 grams packs
the 900 gram pack will be over after 900gramms/144gramms = 6.25 days already
do you understand?
ok that was it i guess, you can close this case with .solved if there are not any questions anymore