#help

[hallow parrot]

can you get b if c=√ a^2-b^2

[rich zenith]

You mean solve for b?

[hallow parrot]

yeahh

[rich zenith]

$\c = \sqrt{a^2 - b^2}$

[rose widget]

adonhs

[rich zenith]

yeah you can

[hallow parrot]

how

[rich zenith]

first get rid of the root

how do we do that?

[hallow parrot]

transpose?

[rich zenith]

you mean squaring?

[hallow parrot]

oh

[rich zenith]

we need this:

$\c^2 = \bigg(\sqrt{a^2 - b^2}\bigg)^2$

[rose widget]

adonhs

[rich zenith]

So the square root cancels out with the root

[hallow parrot]

so if c=√ a^2-b^2 then b= c-b

[rich zenith]

the previous one was correct

$\c^2 = a^2 - b^2$

Actually there is one problem to that task

we need absolute values because we don't know if $a^2 - b^2$ can become negative

Like if b is bigger than a we get something negative

[hallow parrot]

well b is never bigger than a in the equation

[rich zenith]

ok if that is so we can leave the absolute values out

[rose widget]

adonhs

[rich zenith]

Now you can add* b² on both sides

$\b^2 + c^2 = a^2$

[rose widget]

adonhs

[rich zenith]

Now you can subtract c² on both sides

$\b^2 = a^2 - c^2$

[rose widget]

adonhs

[rich zenith]

Now you can take the square root on both sides

$\ \sqrt{b^2} = |b| = \sqrt{a^2 - c^2}$

[rose widget]

adonhs

[rich zenith]

Do we know if a, b and c can be 0 or all positive values? If so we can leave the absolute value again

Seems like the pythagora theorem so I guess a, b, c are positive numbers

So actually

$\ \sqrt{b^2} = b = \sqrt{a^2 - c^2}$

[rose widget]

adonhs

[rich zenith]

That should be it

[hallow parrot]

trhank youu

[rich zenith]

If that's it you may close the case with .solved

[hallow parrot]

wait leme try and solve 1thing

wait if we solve for a

then b^2+c^2=a^2?

.solved

[kind narwhal]

Solved

Post marked as solved by @hallow parrot.

Use .unsolved if this was a mistake.

[rich zenith]

you forgot the to take the square root on both sides

but yea that would be basically it

$\ \sqrt{a^2} = a = \sqrt{b^2 + c^2}$

[rose widget]

adonhs

[hallow parrot]

tyy

[rich zenith]

yeah because a² = b² + c² is not solved for a but for a² really important 🙂

you understand?

[hallow parrot]

yeahh ty

[rich zenith]

nice well done

[hallow parrot]

.solved