#Polynomial
9 messages · Page 1 of 1 (latest)
k not given?
yes
I found the roots of the polynomial P(x-1) as 3 and 2, in this case K is 4, but I could not continue.
P(x-1)= (x-3)(x-2)
No, not k= 4, k= -4.
finally i solved
9 messages · Page 1 of 1 (latest)
Given that P(x) and Q(x) are polynomials, the following equalities hold:
[ P(x-1) = (x-3)(2x+k) ]
[ P(x+1) = x*Q(x-1) ]
What is the value of Q(4) according to this information?
k not given?
yes
I found the roots of the polynomial P(x-1) as 3 and 2, in this case K is 4, but I could not continue.
P(x-1)= (x-3)(x-2)
No, not k= 4, k= -4.
finally i solved