#derivative of tan(θ)
10 messages · Page 1 of 1 (latest)
This is so weird.
This is how you find the derivative of tanx 😉
X=Theta.
Same difference.
It would do you much better to think of tan (theta) as equal to (sin(theta)/cos(theta)), and then differentiate using the quotient rule
But for trigonometric derivatives they work well when plugged into the difference quotient if you really want to do that, some knowledge of trig identities and you should be fine
Yeah thx, I was aware of that way of finding the derivative but I was just trying to get a deeper understanding and tried this with polar coordinates but it doesn't work, obviously. I still don't quite comprehend why it can't work.
That is a question I don’t think I have the answer to honestly, but I think it may have to do with the fact that you’re trying to use implicit differentiation where it isn’t applicable
you’d want to reframe the problem differently, that is for sure. Do you know about implicit differentiation?