#Trigonometric substitution problem
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The antiderivative of -csc(x)cot(x) is csc(x)
So the negative sign disappears with that
But if u use u = sin theta u don’t have to deal with cscxcotx
Idk I’m just confused
Csc x is 1/sin x
You seem to have done it as 1/cos x
Why wouldn’t it be 1 / cos x