static warren
Hi! I am doing for practice a competition exercises, and I got a little problem with one.
The task is: (its translated from Hungarian to English)
As shown in the picture below, there are three regular hexagons in a rectangle. The rectangle
has an area of 80 m2. What is the area of a hexagon?
And here is a picture about the rectangle.
The problem is that I don't know how to start it or what to do with this.
royal narwhalBOT
trail tendon
thats a very complex one bro
you can get the answer form some paid web
get there bro
static warren
I did this sum I might be wrong by all means but I got 17.143 m^2 as my answer
languid haven
you can get the answer form some paid web
get there bro
That's a decidedly unhelpful response. If you don't have concrete help to offer, it would be better to not say anything.
trail tendon
oh ok bro
alpine zephyr
this should be easy you just rearrange it into something simpler
hm
well the height is 3/4 of the orifginal, but the width change you can't see
it's like, 6/7?
yeah the hexes take up 18/28 of the rectangle
you can also count equilateral triangles, which there are 6 in each
18 filled, and 10 empty: 18/28
charred adder
I would just set it up like the side length of the hexagon is x.
Then from there calculate the area of the rectangle in terms of x.
Then equate it to the actual area of the rectangle and solve for x.
Then you can find the area of a hexagon because you know its side length.
static warren
I mean Ik its a long process it might also be wrong but I'm just sharing an idea that I sort of brainstormed
static warren
Hi! I am doing for practice a competition exercises, and I got a little problem ...
Is the person who was trying to solve this problem even here?
static warren
Is the person who was trying to solve this problem even here?
hey
thank you
I am here