#help pls

604 messages · Page 1 of 1 (latest)

ionic copper
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help me with couple of questions pls🙂

heavy cedarBOT
ionic copper
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someone help me pls!!!!!!!😔

kindred peak
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Solve the brackets first then bring all the x on one side and the other numbers on the other side

ionic copper
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okay

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so would it be 5x-10=-6x-18+4

kindred peak
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Yup

ionic copper
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would it then be -x+24?

kindred peak
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Pay attention on the plus and minus in the equation

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If it’s -6x you need to add 6x on both sides

ionic copper
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ohhh ok

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would i add the 6x to 5x or -10

kindred peak
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To 5x

ionic copper
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okay

kindred peak
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Always bring all the x together

ionic copper
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so it would then be 11x-10=-18+4?

kindred peak
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Yup

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Now bring the -10 to the other side

ionic copper
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11x=-18-10+4?

kindred peak
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Remember it’s minus 10

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In that case do you need to add or subtract 10?

ionic copper
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add?

kindred peak
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Yup

ionic copper
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would i need to add to the other side?

kindred peak
ionic copper
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okay

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so 11x=-8+4?

kindred peak
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Yup

ionic copper
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would i then add 8 to -8?

kindred peak
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No just calculate the right side

ionic copper
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11x=-4

kindred peak
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Then divide everything with 11

ionic copper
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x=-4/11?

kindred peak
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Yup

ionic copper
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help with this one pls

ionic copper
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@kindred peak

paper pond
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,rotate

fresh groveBOT
kindred peak
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Sry I just saw that

kindred peak
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So first calculate the left side and then bring all the y on one side

ionic copper
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would that be 4y-15+2=19?

dense plover
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to solve it you need to bring all the y on one side of equality sign and all the normal numbers to the other side

dense plover
ionic copper
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but what would i do from there?

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wait wouldnt i do +15 to the -15 and +15 to 19?

dense plover
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What

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you add +15 because you need the -15 in first part to disappear and to do that you need to add +15, but you add +15 to both sides of the equation so it stays correct and equal, so it will be 4y - 15 + 15 + 2 = 19 + 15

dense plover
ionic copper
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yuh

dense plover
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same thing

ionic copper
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would it now be 4y+2=34?

dense plover
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yes

ionic copper
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would i then add 2 onto the 34?

dense plover
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Why?

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if you add it will be 4y + 2 + 2 = 34 + 2

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but you need 2 to be gone

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So you subtract 2 instead (from both sides)

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or you could say that you add -2 to both sides because -2 = +(-2)

ionic copper
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ohhh ok

dense plover
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if you want a number to be gone from a side then you need to add a number like that but with the opposite sign, for example if you want to remove 2 you add -2 to both sides, if you want to remove -6 then you add +6 to both sides

ionic copper
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okok thanks

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how do i do that

kindred peak
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This is correct

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Solve it like last time

ionic copper
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3m = 20-m?

kindred peak
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Yup

ionic copper
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would i add 20 onto -20?

kindred peak
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You need to bring all the m on one side

ionic copper
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3m-m=20?

kindred peak
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It’s +m

dense plover
ionic copper
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okay

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4m = 20?

dense plover
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Yes

ionic copper
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m=5?

dense plover
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yes

ionic copper
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how would i do the rest of that equation

dense plover
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,rotate

fresh groveBOT
dense plover
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you know that you can also calculate numbers in equations and not just move them around?
for example, in -3x - 3 - 2 = 4x - 5x + 15 we can add -3 and -2 , that would be -5, and 4x - 5x = -x ( we can do that since they both are with x) and then it would look like -3x -5 = -x +15

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so if you were to solve this way

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@ionic copper

dense plover
ionic copper
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sorry for responding late and thanks

ionic copper
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someone help me with the rest of this pls

blissful kiln
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3(5-4x)=(6x-3)/4

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4(15-12x)=6x-3

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60-48x=6x-3

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63=54x

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Hence x= 63/54

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Hence x = 7/6

ionic copper
blissful kiln
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On the right part of the equation

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The (6x-3) is divided by 4

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So to cancel the division, we need to multiply both sides by 4

ionic copper
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okay thanks

rose atlas
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8y-8=5y+10

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8y=5y+18

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3y=18

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y=6

ionic copper
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i dont understand

blissful kiln
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@ionic copper what don’t you understand

ionic copper
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the whole thing

blissful kiln
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Ok

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When handling an equation

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You always need to apply anything you do to both sides

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And the whole point of the equation is to isolate a variable

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In this case y

ionic copper
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yeah but theres no 8y

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so why is it 8y-8

blissful kiln
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Because on the left side, the whole side is divided by 8

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So to cancel out the division you need to multiply by 8

ionic copper
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im still confused

blissful kiln
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At first you have (y-1)/5 = (y+2)/8

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We need to cancel out the division on the left and on the right

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How do I do that ?

ionic copper
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idk

blissful kiln
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Dang

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Any ideas

ionic copper
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we gotta divide the demoniator by something

blissful kiln
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Yes

ionic copper
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would that be 40

blissful kiln
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Yes

ionic copper
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ohhh ok

blissful kiln
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Dividing the denominator is the same as multiplying the numerator

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So you need to multiply by 40 on both sides

silent monolith
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Since there is "=" between them you can cross multiply and then expand, and solve for y

ionic copper
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would i multiply the numerator too?

blissful kiln
blissful kiln
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By multiplying by 40 you have

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(40 (y-1))/5 = (40(y+2))/8

ionic copper
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oh ok

blissful kiln
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And this is 8(y-1)=5(y+2)

ionic copper
blissful kiln
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You still have 5 and 8 but those aren’t division

ionic copper
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im so confused

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i thought the 40 gets rid of those numbers

blissful kiln
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It does

ionic copper
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but then why is it there

blissful kiln
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Because it cancels the division but it doesn’t make it disappear

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Since now you have 40/8

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Which isn’t 1

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But is equal to 5

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So there is no more division but only a multiplication

ionic copper
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oh ok

blissful kiln
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Did you understand why we now have 8(y-1)= 5(y+2) ?

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And if yes

ionic copper
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not rlly

silent monolith
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@ionic copper have you ever heard of cross and multiply?

ionic copper
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yeah

blissful kiln
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Maybe watch a video explaining how to solve an equation

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Such as this one

ionic copper
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ok ill watch it

silent monolith
ionic copper
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idk how to do cross multiply

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will this work for any equation?

silent monolith
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"X" is that you are giving the numbers to the numerator

silent monolith
silent monolith
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And then just expand

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By multiplying

ionic copper
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okay

silent monolith
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Is it clear now?

ionic copper
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i tihnk

silent monolith
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Okay I think you should definitely watch YT how to solve this problem

ionic copper
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will do

silent monolith
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That's great

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I hope you get it though

ionic copper
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thank you

silent monolith
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You are welcome

ionic copper
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did i do it right?

silent monolith
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Yeah, that's right

ionic copper
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ok thanks

proud jetty
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Yeah, u can always check by substituting the value u got for y back into the equation

ionic copper
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okok

silent monolith
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To check, y=6
L.S = 6-1/5
=1
R.S =6+2/8
=1
Therefore, R.S =L.S

ionic copper
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i dont understand how formal checks work

silent monolith
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You just plug in the number you get when you solve

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To the original problem

proud jetty
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Example: 2x = 6 --> You find out x = 3 so to check you do --> 2(3) which should equal six not good explanation but u get the point

ionic copper
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oh ok i understand

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i did this equation wrong and dunno how to fix it help pls

dense plover
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you can only cross multiply if both sides are fractions

ionic copper
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ohhh

dense plover
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you can bring +3 to a fraction though

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3 = 18/6

ionic copper
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would i multiply the denominator by 12?

dense plover
dense plover
ionic copper
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both

dense plover
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you could, but you need to multiply both sides for the equation to stay equal and correct so you would get 12((x-7)/6 + 3) = 12((x+1)/2)

ionic copper
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okay

dense plover
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do you understand

ionic copper
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yeah

dense plover
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okay

ionic copper
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nvm i dont understand

dense plover
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okay what you didn't understand?

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show your solution attempt

ionic copper
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idk what to times 12 by

dense plover
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Both sides of equation

silent monolith
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Why 12 if you have 6 as your lowest common multiple?

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Multiply everything by 6

ionic copper
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oh i didnt even realise that

dense plover
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I didn't too

silent monolith
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It's okay

ionic copper
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do i times 6 by the denominator and numerator

silent monolith
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Mhm

dense plover
ionic copper
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okay

silent monolith
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6(x-7/6) +3*6= 6(x+1/2)

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Be careful with the right side

ionic copper
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would it be that?

silent monolith
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6 won't go away if you divide 6 by 2 it gives you 3, so your right side should be something like 3(x+1) then expand

dense plover
ionic copper
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cuz i did 6x6 and 6x2

dense plover
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you only multiply the upper part and the lower part when you are trying to get the number with the same value but looking different

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And here you multiply the entire equation

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So you multiply x-7/ 6 normally

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only put 6 in upper part

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I really don't know how to explain this

ionic copper
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was i supposed to multiply the 3?

dense plover
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Of course

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If you don't your equation won't stay correct

ionic copper
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okay

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what would i do now

dense plover
ionic copper
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i have this but idk how to do the rest

dense plover
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Okay this is better

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but you see the lower part is not gone, 6 and 2 is still there

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(6x-42)/6 is 6(x-7)/6

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so what you can do with 6?

ionic copper
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im confused

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how did it turn into 6(x-7)/6

dense plover
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Okay tell me how do you multiply x-7/6 by 6?

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You multiply only the upper part here, so you get what?

ionic copper
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x-42/6?

dense plover
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no , what was in the image was correct

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But it doesn't help remove 6 and 2

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So your goal is to remove 6

ionic copper
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do i divide 6 by 6?

dense plover
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yes

ionic copper
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okay

dense plover
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for example you need to remove the 2 on this image

ionic copper
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im confused again

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i remove 4 and 2?

dense plover
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this works because

ionic copper
dense plover
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Okay, so what is 4(5 + 1/2)?

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What does it mean?

ionic copper
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its a fraction

dense plover
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Okay and what is a fraction and what can you do with it?

ionic copper
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a fraction is like how many u have of something and i think i can times 4 by whats in the brackets

dense plover
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What do you know about division?

ionic copper
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how much of something can be divieded by a number

dense plover
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Yes

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Do you know any rules and properties of it?

ionic copper
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no

dense plover
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okay

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ok this is quite hard to explain

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I will try

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What does this mean?

ionic copper
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wait ill brb

dense plover
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okay

dense plover
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(not the 3/4 thing)

ionic copper
ionic copper
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okay

dense plover
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Wrong reply

dense plover
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but first watch the video, it's very important concept

ionic copper
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okok ill watch the video first

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i finished watching the vid

dense plover
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okay do you understand better now?

ionic copper
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yeah

dense plover
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try solving the original problem again

ionic copper
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okay

dense plover
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post what you get when you solve it

ionic copper
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ok

dense plover
ionic copper
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i think i did it

dense plover
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send your solution

ionic copper
dense plover
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why is it 6x - 42 if you removed both 6?

ionic copper
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i times the 6 by x

dense plover
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you had 6(x-7)/6, you can remove the 6 here as was said in the video, so you get x - 7

ionic copper
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but getting x-7 wouldnt work

dense plover
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Why?

ionic copper
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cuz then u cant add both of the 6x to get 12x

dense plover
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Why do you want 12 x?

ionic copper
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bc when i divide 48/12 i get 4

dense plover
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But if you get x-7 there will be different things and you won't need 12 x

ionic copper
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different things like what

dense plover
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so at first it goes like this:

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do you understand why?

dense plover
ionic copper
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i give up

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im done w math

dense plover
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what grade are you in?

ionic copper
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9

dense plover
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oh wow we learned all this in 7 grade

ionic copper
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ok well its different where i live

dense plover
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not very good school I guess

dense plover
ionic copper
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well ill fail math then

dense plover
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you can try tomorrow if you don't feel like it

ionic copper
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okay

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byebye

dense plover
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bye

reef otter
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did you solve this yet

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if you didnt, just distribute, combine like terms, and divide

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isolate the x

ionic copper
ionic copper
reef otter
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which question

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can you send the pic

ionic copper
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yup

reef otter
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ok so you dont want fractions so to get rid of the fraction multiply every term by the lcm

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in this case its 6

ionic copper
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would 6 get rid of the 2 as well?

reef otter
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yes

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so that would leave you with

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6x-42 +18 = 3x+3

ionic copper
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doesnt it have to be the same number to cancle each other out?

reef otter
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you dont have to cancel the 2 out completely

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just get rid of the fraction

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you can cross cancel 6 and 2 which is 3

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3 (x+1) = 3x+3

ionic copper
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okay

reef otter
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then combine like terms

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do you know how to do that

ionic copper
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wait how did u get 3x

reef otter
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because i multiplied 6 to every term

ionic copper
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x(3)?

reef otter
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yes

ionic copper
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okay

reef otter
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becuse i cross canceled

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so when you combine like terms

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6x-3x= 3x

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leaving you with

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3x-42+18=3

ionic copper
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okay

reef otter
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-42+18=

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wait lemme think...

ionic copper
reef otter
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-24

reef otter
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because i want to isolate the variable (x)

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i put them all to one side of the equation

ionic copper
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yeaj but theres no -3x

reef otter
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ohh

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thats bc i substracted 3x on both sides

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sry for the confusion

ionic copper
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its ok

reef otter
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ok so

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the equation would become

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3x-24=3

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add 24 on both sides

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3x = 27

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but you'd only want x so divide by 3

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therefore, x=9

ionic copper
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wait

reef otter
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ok

ionic copper
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i checked the answer sheet and it says x=4

reef otter
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oh

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lemme do it again

ionic copper
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okay

reef otter
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omg

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im so stupid

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so

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i multiplied 6 for all terms right

ionic copper
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yeah

reef otter
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so that would get rid of the fraction

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so the firsst term would become x-7

ionic copper
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wouldnt it be 6x-7?

reef otter
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how did you get that

ionic copper
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bc ur multiplying x too

reef otter
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x-7/6 is one term

ionic copper
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i think u would have to multiply 3 too

reef otter
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yeah you have to multiply 3

ionic copper
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why wouldnt i multiply x tho?

reef otter
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you mean on the first term?

ionic copper
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yeah i think

reef otter
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Because x-7/6 is one term you would multiply 6, but that would only cancel out the 6.

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the /6*

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Which leaves you with x-7

ionic copper
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okay

reef otter
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Question: (x-7)/6 + 3 = (x+1)/2

Multiply every term by 6
x-7+18=3x+3

Combine like terms
x+11=3x+3
-2x=-8

Divide to isolate the variable
x=4

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I hope that helps

ionic copper
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how did u get -2x

reef otter
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-3x on both sides of the equation

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3x-3x = 0

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x-3x=-2x

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(i gtg sorry bye :))

ionic copper
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bye

ionic copper
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@dense plover help me

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pls

dense plover
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Hello

ionic copper
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can u help w the same question from yestreday

dense plover
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yes

ionic copper
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okay thanks

dense plover
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okay so what have you learned and how far you got in solving it?

ionic copper
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i dont think i learned anything and i erased all my work of solving it

dense plover
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and about fractions?

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you didn't learn anything?

ionic copper
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well ig i did learn some stuff

dense plover
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what exactly

ionic copper
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i have to cancle the denominator

dense plover
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okay and how to do that?

ionic copper
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and isolate the x

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i have to times it by something

dense plover
ionic copper
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but idk what to times it by

dense plover
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you need to pick one that so both denominators are gone

ionic copper
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it would be 6 but how would it take away 2 tho?

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bc its not the same number

dense plover
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6 is 3*2, so you cancel out 2 and you are left with 3

ionic copper
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okay

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and i times 6 by x and the 7 too?

dense plover
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Why if you cancelled out the 6?

dense plover
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When you cancel out 6, it means that you divide 6 by 6 and get one so you just get 1 (x-7) which is same as x-7 because multiplying by 1 doesn't do anything

ionic copper
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oh ok

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would it then be x-7+3=x + 1 + 3

dense plover
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no, when you multiply both halves you multiply everything in it that is separated by + or - , so you multiply 3 also

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you only cancelled out 6 that was multiplying the x-7/ 6, but 3*6 stayed

ionic copper
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so i remove 3 then?

dense plover
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Why?

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3 has no relation to the fraction

ionic copper
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wait can i send u a picture and u tell me what i did wrong

dense plover
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Yes

ionic copper
dense plover
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You multiply both the fraction and the 3

ionic copper
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i thought i wouldnt multiply the fraction

dense plover
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You multiply it by 6 so you can divide by 6 (fraction is division by denominator) so it becomes x-7

ionic copper
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okay

dense plover
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also, what is the sign between 3 and (x+1) in second side?

ionic copper
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equal sign

dense plover
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what

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no I mean after you cancel out 2 in second half , what will stay?

ionic copper
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3?

dense plover
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yes

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and then what does that 3 do?

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it multiplies (x+1)

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by the way 3(x+1) means 3 * (x+1)

ionic copper
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ik

dense plover
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okay so now try doing question again

ionic copper
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okay

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is that part right?

dense plover
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Why didn't you multiply the 3 in first half?

ionic copper
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im confused

dense plover
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So x-7/6 and 3 are separated by + sign (or it could also be -) so you multiply both the x-7/6 and the 3

ionic copper
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what do i multiply it by

dense plover
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You are multiplying the entire equation by 6, so you multiply everything by 6

ionic copper
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okay

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6x-42 + 18 = 3x + 3?

dense plover
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no, you canceled out 6 in the fraction

ionic copper
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u said i multiply everything by 6 tho

dense plover
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yes

ionic copper
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so how is it wrong

dense plover
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6(x-7) indeed 6x - 42

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But then you don't have any other 6 to remove the denominator

ionic copper
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so i wouldnt multiply the equation then?

dense plover
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do you multiply it, however that 6 goes away to cancel the denominator, so in the end you are not actually multiplying it

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and just get x-7

ionic copper
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okay

dense plover
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in this example, 7 was divided by 7 (since division is same as fraction, 5/7 is same as 5 : 7)

ionic copper
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i dont understand why we're dividing 7

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oh wait nvm

dense plover
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to remove the fraction , the denominator

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Okay

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try solving the question again

ionic copper
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okay

dense plover
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also what country are you from?

ionic copper
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canada

dense plover
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your native language is English?

ionic copper
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yeah

dense plover
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okay

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watch this video, I think it explains well

ionic copper
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okay

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thanks

dense plover
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okay so have you understood some things?

ionic copper
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yeah but i still cant figure out how to do the question

dense plover
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Okay so start with removing denominators. How to do that?

ionic copper
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i multiply by 6

dense plover
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Okay do it on paper

ionic copper
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okay

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i did what next

dense plover
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send image of what you did

ionic copper
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i just don’t know how to remove 2 tho

dense plover
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Why didn't you multiply 3?

ionic copper
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idk but ill do it

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3 removes the 2 right?

dense plover
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You can't cancel out 6 in first side yet, you need to rewrite it as 6(x-7)/ + 3*6, otherwise the equation will go wrong because then you won't multiply 3

ionic copper
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okay

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like that?

dense plover
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when you have brackets multiplied by something, you multiply all things in brackets that are separated with + or -

dense plover
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And only then you can cancel out 6

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because else +3 will not let you do that

ionic copper
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okay

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would the next part be that?

dense plover
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almost, you lost the 3 in second half

ionic copper
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do i replace 1 with three?

dense plover
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only the image , not the text after it

ionic copper
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ok

dense plover
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so what will you get?

ionic copper
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idk

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ill send u a pic

dense plover
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Okay

ionic copper
dense plover
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it's correct until 2x + 18 = 10

ionic copper
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what did i do wrong

dense plover
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wait you also forgot to multiply X in second half by 3

ionic copper
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oh i didnt know i had to multiply x too

dense plover
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okay wait , explain to me why should both halves (sides) of equation be multiplied by the same number?

ionic copper
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idk

dense plover
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so it all stays equal

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And so it doesn't go wrong

ionic copper
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oh

dense plover
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so you have to multiply both sides by 6

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and then 6 can be replaced as 3 * 2 in the second side, so you get 3 * 2 (x +1)/2, and since it's multiplication and division (fraction) here, you can cancel out both 2's

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because 2 : 2 = 1,

ionic copper
#

so i write it like that?

dense plover
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Yes

ionic copper
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okay

dense plover
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what you do next?

ionic copper
#

do i do that?

dense plover
#

Yes

ionic copper
#

okay

#

would that be the next part?

dense plover
#

why it put my message here?

ionic copper
#

no clue

dense plover
#

I meant to say what is 3 * (x+1)?

dense plover
ionic copper
#

oh ok

dense plover
#

so in second side it will be 3x + 3

ionic copper
#

ok

dense plover
#

now what will you get?

ionic copper
dense plover
#

yes but please remember that we do with x like with normal number, so when you want to remove the x from a side , you do add x with the opposite sign

#

So here you wanted to remove 3x from the second side

ionic copper
#

oh ok lemme re-write it

dense plover
#

so you do like you did with 7

#

Okay

ionic copper
#

like that?

dense plover
#

why you +3x to first side? You do -3x to both sides otherwise the equation will no longer be correct and sides won't be equal

ionic copper
#

oh ok

dense plover
#

okay remember that you remove X like any normal number, just like you did with 7 in this equation

ionic copper
#

would it then be 2x?

dense plover
#

x-3x = ?

ionic copper
#

-2x

dense plover
#

yes

ionic copper
#

-2x - 7 +18 = 3?

dense plover
#

yes

ionic copper
#

i would then add 7 to -7 and 3 right?

dense plover
#

yes

ionic copper
#

-2x+18=10?

dense plover
#

yes thats right

ionic copper
#

i then add the 18 and 10 together?

dense plover
#

why add?

#

to remove 18, you do -18 to both sides

ionic copper
#

oh ok

dense plover
#

don't let the -2x confuse you

ionic copper
#

-2x = -8?

dense plover
#

yes

#

now divide both sides by -2

#

(because -2 is the one with x)

ionic copper
#

okay

#

so its 4 then?

dense plover
#

Yes

#

you solved it

ionic copper
#

no way after so long

#

thanks

dense plover
#

also, you might want to find a paid tutor in real life and ask all the questions and things you don't understand to that tutor

#

because its hard to explain in internet

ionic copper
#

yeah im getting a tutor soon

dense plover
ionic copper
#

yuh

dense plover
dense plover
# ionic copper yuh

also, when you do get a tutor ask about all things you don't understand and don't stop asking until you finally understand, because math is built on logic and you can't really use logic if you don't understand things

ionic copper
#

okok thanks

dense plover
#

👍,
bye👋

ionic copper
#

byebye

#

.close