#domain of composite pair of functions
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<@&286206848099549185>
whatsup
@junior crag
ping me if help
For f(x)=1/(x+3) , g(x)=1/(x-9) the domain of f(g(x)) would be (-inf,-3)U(-3,9)U(9,inf) right?
@junior crag
Just wondering if this is correct answer
no because
f has all domain except when x=3
but x is now g
so g cant be 3
solve that and then u willl know the domain
But wouldn’t f be x≠-3
but x is replaced with g
so f is 1/(g+3)
obviosuly g cant be -3
but also x cant be -3
because it was orginally undefined there
So x=+3
?
This is what I have for my work but I don’t know how to solve for f(g(x))
you dont need f(g)
unless it says so
just plug in g for x
Well the problem says to find the domain for f(g(x)
When plugging in g in the problem for f(x) I get 1/((1/x-9)+3/1))
@junior crag
well so u have to account for domain of f without g, domain of g, and the domain breaks of f evaluate at g instead of x
you dont even need f(g)
Oh so just domain of f and g?
yea
and all the places where domain of f is broken substitute for g as well after using nromal x
On math way it says one of the domains is 26/3 but I got 1/12 this time