#Limits help

19 messages · Page 1 of 1 (latest)

slate snowBOT
little hornet
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for question 6
is that the only way to prove it
because i disproved it by saying LHL=5 and RHL=-1/3
therefore LHL != RHL and the limit does not exist

slate snowBOT
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Limits help

magic jewel
little hornet
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Is this what u were asking for ?

magic jewel
little hornet
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No for the LHL I plugged in -3 and for the RHL I plugged in -1

magic jewel
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i think if you demonstrate more examples like LHL -3 -2.5 -2.1 and so on and for RHL: -1, -1.5, -1.9

little hornet
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For previous questions I used this method and it corespponed with the answer

magic jewel
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my point is i could also plug in for LHL: -1000 and for RHL: 1000 but the question is are they saying something about the limit at -2?

little hornet
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In the solution they used -1.999 and -2.001 do I have to use those bounds too

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Because I can prove it without being that accurate

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They didn’t ask to show how it behaves so I though I could get away with how I did it

magic jewel
# little hornet In the solution they used -1.999 and -2.001 do I have to use those bounds too

That's intentional because these values are very near -2 and thus you can make a better conclusion of the limits.
Proving without accuracy can work sometimes but it's not very beneficial, because by your statement I can plug any numbers that are outside of -2

Like LHL: -1000 and RHL: 1000 (really extreme)

I mean LHL: x = -3 => you get 5 and RHL: x = -1 you get -1/3
That's a good starting point but elaborating further on what happens with another approach from both sides like
LHL: x = -2.5 and RHL: x = - 1.5 and then comparing the outputs from your previous approaches, then you can make a more firm statement regarding the limits on both sides

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This was my point

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Because u asked if "your way" to prove is also right but basically you did the same thing like them, by pluggin some near value and then make a statement how the limits are from both sides.

I mean, imagine you don't know how the functions looks like.
By making some approaches and comparing the outputs you can form a better understanding proof regarding limits

little hornet
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oh i understand now